Recall this kinematic equation:
a = 
This equation gives the acceleration of the object assuming it IS constant (the velocity changes at a uniform rate).
a is the acceleration.
Vi is the initial velocity.
Vf is the final velocity.
Δt is the amount of elapsed time.
Given values:
Vi = 0 m/s (the car starts at rest).
Vf = 25 m/s.
Δt = 10 s
Substitute the terms in the equation with the given values and solve for a:
a = 
<h3>a = 2.5 m/s²</h3>
Answer:
The electric field is directed toward the electron and has a magnitude of
.
Explanation:
An electric field is define as the surrounding of charges which exert a force on each other and this force can be attractive or repulsive depends on the charge.
In the given case electron is given and the magnitude of charge on electron is 
Electric field can be represented as,

Here, r is the distance between the point ande charge, k is the electric field constant and Q is the charge.
In the given question an electron is given so electric field will be,

As we know that electric field start from the positive charge and vanish in the negative charge.
So, here the electric field will be
and it is directed toward the electron because of negative charge on the electron.
Answer:
400 kilogram
Explanation:
Force exerted is directly proportional to the mass of an object.
F=ma where m is mass and a is acceleration. Taking uniform acceleration on all objects then the larger the mass the higher the force and vice versa. Theredore, among the masses given, 400 kilograms is the largest hence it exerts the largest force at the bottom