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torisob [31]
3 years ago
12

In regard to self-modification, a program of intervention should be designed to increase or decrease target behavior. T F

Physics
2 answers:
larisa [96]3 years ago
7 0
True my dude............................
Aleks [24]3 years ago
7 0

Answer:

True

Explanation:

When it comes to self-modification, this is usually done through a program particularly designed for this purpose. This would be a program of intervention. A program of intervention needs to be designed to increase or decrease target behaviour. In other words, for it to be considered functional, the program should address whatever behaviour needs to be modified.

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A description of both speed and direction
julia-pushkina [17]
Speed most often describes acceleration or a high rate of motion. ... As a verb, it means to “move along quickly,” like how you speed around on your bike. Direction is defined as the path that something takes, the path that must be taken to reach a specific place, the way in which something is starting to develop or the way you are facing
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3 years ago
Why would you wanna know a cure for all sickness.?
Alchen [17]

Answer:

because if someone close to u gets sick you would know how to cure it

4 0
3 years ago
A box rests on a horizontal, frictionless surface. a girl pushes on the box with a force of 17 n to the right and a boy pushes o
Komok [63]
Refer to the diagram shown below.

The net force acting on the box is 17 - 13 = 4 N to the right.
The box moves on a friction surface by 3.5 m to the right.

By definition,
Work = Force x Distance.

(a) The work done by the girl is
     W₁ = (17 N)*(3.5 m) = 59.5 J

(b) The work done by the boy is
     W₂ = (13 N)*(-3.5 m) = - 45.5 J

(c) The work done by the net force  is
    W₃ = (4 N)*(3.5 m) = 14 J

Note that W₃ = W₁ + W₂

Answers:
(a) 59.5 J
(b) - 45.5 J
(c) 14 J

5 0
3 years ago
You have an initial velocity of - 3.0 m/s . You then experience an acceleration of 2.5 m/s ^ 2 for 9.Oswhat is your final veloci
storchak [24]

Answer:

The final velocity of your motion is 19.5 m/s.

Explanation:

Given;

initial velocity of your motion, u = -3.0 m/s

acceleration of your motion, a = 2.5 m/s²

time of your motion, t = 9.0 s

The final velocity of your motion is calculated as follows;

v = u + at

where;

v is the final velocity

substitute the given values and solve for v

v = -3.0 + (2.5 x 9)

v = -3.0 + 22.5

v = 19.5 m/s

Therefore, the final velocity of your motion is 19.5 m/s.

4 0
3 years ago
A 2.66 kg, 22.25 cm diameter turntable rotates at 238 rpm on frictionless bearings. Two 420 g blocks fall from above, hit the tu
Phantasy [73]

Answer:

The value is w_f  =  146 \  rpm

Explanation:

From the question we are told that

  The mass is  m  =  2.66 \  kg

  The diameter is  d =  22.25 \ cm  = 0.2225 \  m

   The angular speed is  w_i =  238 \  rpm

   The mass of each of the blocks is m_b  =  420 \ g  =  0.420 \  kg

Generally the radius of the turntable  is mathematically represented as

        r =  \frac{d}{2}

=>     r =  \frac{0.2225}{2}

=>     r =  0.11125

The moment of inertia of the turntable before the blocks fell is mathematically represented as

         I_{i} =  \frac{1}{2} * m  *  r^2

=>       I_{i} =  \frac{1}{2} * 2.66  *  (0.11125)^2

=>       I_{i} =  0.01646 \ kg\cdot m^2

The moment of inertia of the turntable after the blocks fell is mathematically represented as

         I_{f} =  \frac{1}{2} * m  *  r^2 + 2 m_b * r^2

=>       I_{f} =  \frac{1}{2} * 2.66  *  (0.11125)^2 +  2 * 0.420 * 0.11125^2

=>       I_{f} =  0.02686 \ kg\cdot m^2

Generally from the law of angular momentum conservation  

          L_i = L_f

Here L_i is the initial  angular momentum of the turntable  before the blocks fell which is mathematically represented as

        L_i =  I_i *  w_i

and  L_f is the initial  angular momentum of the turntable after the blocks fell which is mathematically represented as

       L_i =  I_f *  w_f

So

      0.01646*  238 =  0.02686 * w_f

=>    w_f  =  146 \  rpm

5 0
3 years ago
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