Answer: 3.2 * 10^-3 C
Explanation: In order to solve this problem we have to use the Coulomb force given by:
F=k*q^2/ d^2 where he consider the same charge for each point
so, we have
q^2= F*d^2/k= 1.137* (10 C*9*10m)^2/9*10^9 N*m^2/C^2)=3.2 * 10^-3 C.
The examples may be;
making yogurt; If you heat beyond 130F you kill the cultures. The higher the temperature up until that point the faster it cultures until you close in on killer temperature.
Mixing 2 part epoxy; Keep it cool and the reaction time is delayed. On the other hand, heat it up and epoxy reacts quicker. In the winter time and close to 35 Degrees, the reaction time for cement to harden can take 400% more time to set.
Answer:
degree celsius
Explanation:
it's measured in degree Celsius
Answer:
The magnitude of the average frictional force on the block is 2 N.
Explanation:
Given that.
Mass of the block, m = 2 kg
Initial velocity of the block, u = 10 m/s
Distance, d = 50 m
Finally, it stops, v = 0
Let a is the acceleration of the block. It can be calculated using third equation of motion. It can be given by :



The frictional force on the block is given by the formula as :
F = ma

|F| = 2 N
So, the magnitude of the average frictional force on the block is 2 N. Hence, this is the required solution.