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3 years ago

Write the complete balanced equation for the following reaction: S8 + O2 yields SO3

2 answers:

7 0

Hello!! In order for your equation to be balanced, you need to have all things equal the same thing on each side. Therefore, your equation would read:
3 S(sub 8) + 12 O(sub 2) -> 8 SO(sub 3)
This would allow everything to equal 24.
I hope this has helped you and if you need any more questions answered with balancing, let me know. Have a great day!!

aleksklad [387]3 years ago

3 0

S8 + 12O2 yields 8SO3

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Rank the following substances in order from most soluble in water to least soluble in water: methane, CH4; 2-butanol, C4H9OH; ma

Taya2010 [7]

Answer: The given substances are placed in order from most soluble in water to least soluble in water as follows.

$MgCl_{2}$ > $C_{4}H_{9}OH$ > $C_{3}H_{8}$ > $CH_{4}$

Explanation:

It is known that like dissolves like which means a polar compound will be soluble in a polar solvent. And, a non-polar compound will be soluble in non-polar solvent.

Ionic compounds are soluble in polar solvent like water. For example, $MgCl_{2}$ is an ionic compound and it is readily soluble in water.

2-butanol ( $C_{4}H_{9}OH$ ) is also a polar compound and it will also dissolve in water but to a lesser extent as compared to magnesium chloride.

Whereas both methane and propane are non-polar in nature. But as propane is larger in size as compared to methane so, it will be slightly more soluble in water as compared to methane.

Thus, we can conclude that the given substances are placed in order from most soluble in water to least soluble in water as follows.

$MgCl_{2}$ > $C_{4}H_{9}OH$ > $C_{3}H_{8}$ > $CH_{4}$

5 0

3 years ago

40 POINTS!!

natali 33 [55]

I'm not sure if this is the exact answer for I do not learn this in school yet. But I hope this helps!

3 ZnS + 2 AlP = Zn3P2 + Al2S3

- Kana

4 0

3 years ago

Hemoglobin in your blood does not use elemental iron. It uses iron in the form of Fe2+(aq).

valina [46]

Explanation:

Balanced chemical reaction equation will be as follows.

$2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)$

In human body, the neutral iron changes into $Fe^{2+}$ (aq) cation. There will be an oxidation-half reaction and a reduction-half reaction. Equations for this reaction are as follows.

Oxidation: 2Fe^{2+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + 2e^{-}[/tex] .... (1)

Reduction: $2H^{+}(aq) + 2e^{-} \rightleftharpoons H_{2}(g)$ ...... (2)

On adding both equation (1) and (2), the overall reaction equation will be as follows.

$2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)$

Therefore, neutral iron is a part of Heme - b group of Hemoglobin and in an aqueous solution it dissolutes as a part of Heme group. Hence, then it becomes an $Fe^{2+}$ cation.

3 0

3 years ago

Which is the first step to take to help reduce pollution

rjkz [21]

B. Gain information about the current state of the environment and ways to improve it.

6 0

3 years ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

2 years ago