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amm1812
3 years ago
11

Which of the following is TRUE?

Chemistry
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

Explanation:

For a general equilibrium

aA +bB ⇔ cC + dD ,

the equilibrium constant is K = [C]^c [D]^d / [A]^a[B]^b.

Our reasoning here should be based on the fact that  Q has the same expression as K, but is used when the system is not at equilibrium, and the system will react to make Q = K to attain it ( Le Chatelier´s principle ).

So with this in mind, lets answer this question.

1. False: Q can large or small but is not the value of the equilibrium constant, it will predict the side towards the equilibrium will shift to attain it.

2. False: Given the expression for the equilibrium constant, we know if K is small the concentrations of the reactants will be large compared to the equilibrium concentrations of the products.

3. False: when the value of K is large, the equilibrium concentrations of the products will be large and it will lie on the product side.

4. True: From our previous reasongs this is the true one.

5. False: If K is small, the equilibrium lies on the reactants side.

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A gamma ray primarily consists of pure energy and no mass. True False
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This is true otherwise cancer patients would have a hole in them and so would the hulk ;)
3 0
3 years ago
The pressure inside a compressed gas cylinder is 144 atm at 48°C. What will the pressure inside the cylinder be after it is cool
Andrews [41]
<h3>Answer:</h3>

134 atm

<h3>Explanation:</h3>
  • Based on the pressure law, the pressure of a gas varies directly proportionally to the absolute temperature at a constant volume.
  • Therefore; we are going to use the equation;

\frac{P1}{T1}=\frac{P2}{T2}

In this case;

Initial pressure, P1 = 144 atm

Initial temperature, T1 (48°C) = 321 K

Final temperature, T2 (25°C) = 298 K

We need to find the final pressure,

Therefore;

P2 = (P1/T1)T2

    = (144/321)× 298 K

    = 133.68 atm

   = 134 atm

Therefore, the new pressure will be 134 atm.

5 0
4 years ago
Determine the formula weight of BeCl₂.
tia_tia [17]
Be= Beryllium= weight 9.01
Cl= Chlorine= weight 35.45
Since there are 2 Chlorine, you have to add Chlorine twice.
9.01 + 35.45 + 35.45= 79.91

Answer: 79.91
(This answer does not include sig.figs)
4 0
3 years ago
A temperature change in a reaction indicates_____.
natita [175]

A temperature change in a reaction indicates a chemical change

8 0
3 years ago
Read 2 more answers
5.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the
cupoosta [38]

Answer: Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

Explanation:

To calculate the entalpy, we use the equation:

q=mc\Delta T

where,

q = heat absorbed by water = ?

m = mass of water = {\text {volume of water}}\times {\text {density of water}}=100.0ml\times 1.00g/ml=100.0g

c = heat capacity of water = 4.186 J/g°C

\Delta T= change in temperature = 6.70^0C

q=100.0g\times 4.184J/g^0C\times 6.70^0C=2803.3J=2.8033kJ

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

The heat absorbed by water will be equal to heat released by MgSO_4

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 5.11 g

Molar mass  = 120 g/mol

Putting values in above equation, we get:

\text{Moles of }MgSO_4=\frac{5.11g}{120g/mol}=0.042mol

0.042 moles of MgSO_4 releases = 2.8033 kJ

1 mole of MgSO_4 releases = \frac{2.8033 kJ}{0.042}\times 1=66.7kJ

Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

3 0
3 years ago
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