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Lina20 [59]
3 years ago
15

The density of silver (Ag) is 10.5 g/cm^3. How do you find the mass of Ag that occupies 965 cm^3 of space?

Chemistry
1 answer:
ra1l [238]3 years ago
4 0
D = m / V

10.5 = m / 965

m = 10.5 x 965

m = 10132.5 g
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Please tell if my answer is right or wrong.
xxTIMURxx [149]
Change the places of 'acts against the motion of an object' and 'causes an object to change speed or direction'
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Identify the oxidizing agent and the reducing agent in the following reactions: (i) 8NH3( g) + 6NO2( g) => 7N2( g) + 12H2O( l
shusha [124]

Answer:

(i)  Oxidizing Agent: NO2 / Reducing Agent NH3-

(ii) Oxidizing Agent AgNO3 / Reducing Agent Zn

Explanation:

(i) 8NH3( g) + 6NO2( g) => 7N2( g) + 12H2O( l)

In this reaction, both two reactants contain nitrogen with a different oxidation number and produce only one product which contains nitrogen with a unique oxidation state. So, nitrogen is oxidized and reduced in the same reaction.

Nitrogen Undergoes a change in oxidation state from 4+ in NO2 to 0 in N2. It is reduced because it gains electrons (decrease its oxidation state). NO2 is the oxidizing agent (electron acceptor).

Nitrogen Changes from an oxidation state of 3- in NH3 to 0 in N2. It is oxidized because it loses electrons (increase its oxidation state). NH3 is the reducing agent (electron donor)

(ii) Zn(s) +AgNO3(aq) => Zn(NO3)2(aq) + Ag(s)

Ag changes oxidation state from 1+ to 0 in Ag(s).

Ag is reduced because it gains electrons and for this reason and AgNO3 is the oxidizing agent (electron acceptor)

Zn Changes from an oxidation state of 0 in Zn(s) to 2+ in Zn(NO3)2. It is oxidized and for this reason Zn is the reducing agent (electron donor).

Balanced equation:

Zn(s) +2AgNO3(aq) => Zn(NO3)2(aq) + 2Ag(s)

 

4 0
4 years ago
Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.
maria [59]
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
5 0
3 years ago
Explain how you could find the mass and weight of an object on Earth, and the mass and weight of the same object on the moon. Ho
Katarina [22]

Answer:

mass of a particular object remains the same where ever it is placed, the mass will remain the same whether the object is on the moon or earth, unlike weight which will change.

Weight is affected by gravity. Therefore it is dependent on gravity or directly proportional to the force of gravity.

weight = mass × gravity

The gravity on earth is much larger than the gravity on the moon. Therefore the weight of an object weighs heavier on earth than on the moon. The object when placed on the moon will have a lower weight.

The difference is that the weight of the object on the moon will be lower than the weight of the object on earth.

The similarity is that the mass of an object will remain the same, regardless if it's placed on the moon or earth.

Hope this helps.

7 0
3 years ago
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