Answer:
S = 21.92 %
F = 78.08 %
Explanation:
To find the percent composition of each element in SF6, we must find the molar mass of SF6 first.
Molar mass of SF6 = 32 + 19(6)
= 32 + 114
= 146g/mol
mass of Sulphur (S) in SF6 = 32g
mass of Fluorine (F) in SF6 = 114g
Percent composition = mass of element/molar mass of compound × 100
- % composition of S = 32/146 × 100 = 21.92%.
- % composition of F = 114/146 × 100 = 78.08%.
D
Nuclear reaction involves the nuclei of atoms. The nucleus can either split (as is the case with fission) of fuse as is the case with nuclear fusion. Remember the main particles in the nucleus are protons and neutrons.
Explanation:
In nuclear fission, atomic nuclei split into lighter atoms through loss of protons and neutrons (such as through loos of a beta particles - 2 protons and 2 neutrons). In the case of fusion, two atomic nuclei fuse under pressure (hence adding neutrons and protons) to create heavier atoms (2 hydrogens can fuse to form a helium). Electrons are not involved in nuclear reactions. Electrons are mainly involved in chemical reactions.
Learn More:
For more on nuclear fission and fusion check out;
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Both scientific laws and scientific theories are not based on hypothesis.
Because , scientific laws are proven and so they are real not hypothetical.
Whereas scientifc theories can be hypothetical.
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The mass of the liquid is 280 g.
Mass = 200 mL × (1.4 g/1 mL) = 280 g
Reaction of dissociation: Ag₂SO₄ → 2Ag⁺ + SO₄²⁻.
m(Ag₂SO₄) = 4 g.
V(Ag₂SO₄) = 1 l.
n(Ag₂SO₄) = m(Ag₂SO₄) ÷ M(Ag₂SO₄).
n(Ag₂SO₄) = 4 g ÷ 311,8 g/mol.
n(Ag₂SO₄) = 0,0128 mol.
n(Ag⁺) = 2 · 0,0128 mol = 0,0256 mol.
n(Ag₂SO₄) = n(SO₄²⁻) = 0,0128 mol.
c(Ag⁺) = n ÷ V = 0,0256 mol ÷ 1 l = 0,0256 mol/l.
Ksp = c(Ag⁺)² · c(SO₄²⁻).
Ksp = (0,0256 mol/l)² · 0,0128 mol/l.
Ksp = 8,3·10⁻⁶.
