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torisob [31]
2 years ago
13

Which of the following would happen if Earth's moon were half the size that it is now? O The oceans' tidal variations would be s

maller because the Moon would exert less gravitational pull on Earth's oceans. O The oceans' tidal variations would be greater because the Moon would exert less gravitational pull on Earth's oceans. O The oceans' tidal variations would be greater because the Moon would exert more gravitational pull on Earth's oceans. The oceans' tidal variations would be smaller because the Moon would exert more gravitational pull on Earth's oceans. & Previous​
Chemistry
1 answer:
Brilliant_brown [7]2 years ago
3 0

Answer: A. The oceans‘ tidal would be smaller because the moon would exert less gravitational pull on earths oceans.

Explanation:

i got it right :)

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Do you think the reflected waves would ever return to the airplane that transmitted them? explain
Ket [755]
No, it is very unlikely for that to happen.
8 0
3 years ago
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Write a balanced net ionic equation for the following reaction: SrCl2(aq) + H2CO3(aq) → SrCO3(s) + HCl (aq)
max2010maxim [7]
  We will balance the equation in the following order: metals, amethals, carbon, hydrogen and oxygen (the most common order).
  The metal present in the equation is Sr, which is already balanced (there are 1 on each side of the equation).
  The amethal present in the equation is Cl. There is 2 Cl in the left side and only one in the right side. So, we will multiply the quantity of the molecule that contains Cl by 2. Doing this, we'll obtain:

SrCl_2_{(aq)}+H_2CO_3_{(aq)}\to SrCO_3_{(s)}+2HCl_{(aq)}
 
  Looking at the equation, we can see that it is now fully balanced. Hence, a balanced equation of the reaction is:

SrCl_2_{(aq)}+H_2CO_3_{(aq)}\to SrCO_3_{(s)}+2HCl_{(aq)}
5 0
2 years ago
Which of these is an acid?
julsineya [31]
My best guess would be c
8 0
3 years ago
Based on the graph below, if you chose an alien at random on day 20, what form would it most likely be in?
ArbitrLikvidat [17]

Answer:

A. Thin

Explanation:

i took the test a while back yw <3

4 0
3 years ago
If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under th
mr_godi [17]

Answer:

The volume of CO2 produced is 6.0 L (option D)

Explanation:

Step 1: Data given

Volume of oxygen = 3.0 L

Carbon monoxide = CO = in excess

Step 2: The balanced equation

2 CO (g) + O2 (g) → 2 CO2 (g)

Step 3: Calculate moles of O2

1 mol of gas at STP = 22.4 L

3.0 L = 0.134 moles

Step 3: Calculate moles of CO2

For 2 moles CO we need 1 mol of O2 to produce 2 moles of CO2

For 0.134 moles O2 we'll have 2*0.134 = 0.268 moles CO2

Step 4: Calculate volume of CO2

1 mol = 22.4 L

0.268 mol = 22.4 * 0.268 = 6.0 L

The volume of CO2 produced is 6.0 L

8 0
3 years ago
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