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torisob [31]
3 years ago
13

Which of the following would happen if Earth's moon were half the size that it is now? O The oceans' tidal variations would be s

maller because the Moon would exert less gravitational pull on Earth's oceans. O The oceans' tidal variations would be greater because the Moon would exert less gravitational pull on Earth's oceans. O The oceans' tidal variations would be greater because the Moon would exert more gravitational pull on Earth's oceans. The oceans' tidal variations would be smaller because the Moon would exert more gravitational pull on Earth's oceans. & Previous​
Chemistry
1 answer:
Brilliant_brown [7]3 years ago
3 0

Answer: A. The oceans‘ tidal would be smaller because the moon would exert less gravitational pull on earths oceans.

Explanation:

i got it right :)

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“What is the group number for the elements that have a stable number of electrons in their outer energy level?”
Studentka2010 [4]

Answer:

A. 18

Explanation:

Sulfur number sixteen forms a negative

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What happens if you were to swallow a small amount if wet nail polish? Answer truthfully in your own words.
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2 years ago
2. List and elaborate on at least two limitations of the 24-hour recall as a
Pavlova-9 [17]

Answer:

The correct answer is - may not be typical, and participant burden.

Explanation:

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5 0
3 years ago
the element carbon has two common isotopes: C-12 (12 U) AND C-13 (13.003355 U). IF THE AVERAGE ATOMIC MASS OF CARBON IS 12.0107
oksian1 [2.3K]

Answer:

The percent isotopic abundance of C- 12 is 98.93 %

The percent isotopic abundance of C- 13 is 1.07 %

Explanation:

we know there are two naturally occurring isotopes of carbon, C-12 (12u)  and C-13 (13.003355)

First of all we will set the fraction for both isotopes

X for the isotopes having mass 13.003355

1-x for isotopes having mass 12

The average atomic mass of carbon is 12.0107

we will use the following equation,

13.003355x + 12 (1-x) = 12.0107

13.003355x + 12 - 12x = 12.0107

13.003355x- 12x = 12.0107 -12

1.003355x = 0.0107

x= 0.0107/1.003355

x= 0.0107

0.0107 × 100 = 1.07 %

1.07 % is abundance of C-13 because we solve the fraction x.

now we will calculate the abundance of C-12.

(1-x)

1-0.0107 =0.9893

0.9893 × 100= 98.93 %

98.93 % for C-12.

7 0
3 years ago
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