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torisob [31]
3 years ago
13

Which of the following would happen if Earth's moon were half the size that it is now? O The oceans' tidal variations would be s

maller because the Moon would exert less gravitational pull on Earth's oceans. O The oceans' tidal variations would be greater because the Moon would exert less gravitational pull on Earth's oceans. O The oceans' tidal variations would be greater because the Moon would exert more gravitational pull on Earth's oceans. The oceans' tidal variations would be smaller because the Moon would exert more gravitational pull on Earth's oceans. & Previous​
Chemistry
1 answer:
Brilliant_brown [7]3 years ago
3 0

Answer: A. The oceans‘ tidal would be smaller because the moon would exert less gravitational pull on earths oceans.

Explanation:

i got it right :)

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Calculate the energy needed to raise the temperature of 42 grams of water from 25.0 degrees Celsius to 48 degrees Celsius. The s
7nadin3 [17]

Answer:

option B is the answer.

B. 8266 calories

4 0
3 years ago
Read 2 more answers
The table shows the amount of radioactive element remaining in a sample over a period of time.
Assoli18 [71]

It would take 147 hours for 320 g of the sample to decay to 2.5 grams from the information provided.

Radioactivity refers to the decay of a nucleus leading to the spontaneous emission of radiation. The half life of a radioactive nucleus refers to the time required for the nucleus to decay to half of its initial amount.

Looking at the table, we can see that the initial mass of radioactive material present is 186 grams, within 21 hours, the radioactive substance decayed to half of its initial mass (93 g). Hence, the half life is 21 hours.

Using the formula;

k = 0.693/t1/2

k = 0.693/21 hours = 0.033 hr-1

Using;

N=Noe^-kt

N = mass of radioactive sample at time t

No = mass of radioactive sample initially present

k = decay constant

t = time taken

Substituting values;

2.5/320= e^- 0.033 t

0.0078 = e^- 0.033 t

ln (0.0078) = 0.033 t

t = ln (0.0078)/-0.033

t = 147 hours

Learn more: brainly.com/question/6111443

7 0
2 years ago
The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

K_a=5.8\times 10^{-10}

Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

(\alpha)=0.000011

[H^+]=c\times \alpha

[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

3 0
3 years ago
Determine the number of protons and neutrons in plutonium-239 and write its symbol in the form azx.
Verizon [17]
94 protons and 145 neutrons
4 0
3 years ago
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Question<br> What is the molarity of a 400 mL solution containing 0.60 moles of NaCl?
Mumz [18]

Answer:

0.24 M

Explanation:

Molarity = Moles solute / Liters solution

Step 1: Identify variables

400 mL = Liters solution

0.60 moles = Moles solute

Step 2: Identify conversions

1 L = 1000 mL

Step 3: Convert mL to L

400mL(1 L/1000mL) = 0.4 L

Step 4: Find molarity

M = (0.4 L)(0.60 mol) = 0.24 M

6 0
3 years ago
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