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klemol [59]
3 years ago
11

I have no idea of how to approach this problem

Physics
1 answer:
nataly862011 [7]3 years ago
4 0

Answer:

p=1

Explanation:

Well me know that v=m/s

and that a=m/s^2

so

(m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1

Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.

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Answer:

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Draw a diagram. Put the two cells in series. Now draw 3 resistors. Two of them equal 0.26 ohms each. The third one is the lightbulb which is 12 ohms.

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