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Anestetic [448]
3 years ago
15

How much work can be done per second by a one horsepower engine? 275 ft.-lbs./sec 550 ft.-lbs./sec 1,100 ft.-lbs./sec 1,650 ft.-

lbs./sec
Physics
1 answer:
Damm [24]3 years ago
5 0
Hello!

Answer:

550 \frac{ft.lb}{sec}

Explanation:

P= \frac{W}{t}

And:

W=F.d

F: Applied force.
d: Distance traveled by the object.

Finally, we have that:

t: Time traveled by the object.

The Power or Work/Second of a 1 Hp (Horsepower) engine is the force necessary to vertically raise a weight of 550 lb at the speed of 1 ft/second

Have a nice day :)



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The fastest pitched baseball was clocked at 47 m/s. Assume that the pitcher exerted his force (assumed to be horizontal and cons
Eduardwww [97]

Answer:

Following are the solution to the given points:

Explanation:

For point a:

Find the schematic of the empty body and in attachment. Upon on ball during the pitch only two forces act:

The strength of the pitcher F is applied that operates horizontally. Its gravity force acting on an object is termed weight, which value is where m denotes mass, and g the acceleration of gravity.

For point b:

160.2\  N

First, they must find that ball's acceleration. You can use the SUVAT equation to achieve that

where

v = 47\  \frac{m}{s} \\\\u = 0 \\\\a =?\\\\d = 1.0 \ m \\\\

Solving for a,

a=\frac{v^2-u^2}{2d}=\frac{47^2-0}{2(1.0)}=1104.5 \ \frac{m}{s^2}

Calculating the mass:

m = 145 g = 0.145 kg

Calculating the force:

F=ma=0.145 \times 1104.5= 160.2 \ N

 For point c:

0.195 times the pitcher's weight

m = 84 \ kg \\\\g = 9.8\ \frac{m}{s^2}\\\\

Solving for W:

W=84 \times 9.8= 823.2 \ N

Now the force of Part B could be defined as the fraction of the mass of the pitcher:  

\frac{F}{W}=\frac{160.2}{823.3}=0.195

4 0
3 years ago
The innermost satellite of jupiter orbits the planet with a radius of 422 × 103 km and a period of 1.77 days. what is the mass o
FinnZ [79.3K]

The mass of Jupitar is obtained from the calculations as 5.8 * 10^-14 Kg.

<h3>What is the mass of Jupitar?</h3>

There are nine planets in the solar system and the sun lies at the enter of our solar system. This is the heliocentric model of the solar system.

Given that;

T^2 = GMr^3/4π

T = period

G = gravitational constant

r = radius

M = mass of Jupitar

Now;

1 day = 86400 seconds

1.77 days = 1.77 days *  86400 seconds/1 day

= 152928 seconds

Making M the subject of the formula;

M =4πT^2/Gr^3

M = 4 * 3.142 * (152928)^2/6.67 × 10^-11 * (422 × 10^9)^3

M = 2.9 * 10^11/5.0 * 10^24

M = 5.8 * 10^-14 Kg

Learn more about mass of a planet:brainly.com/question/13851553

#SPJ1

5 0
2 years ago
Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller
Travka [436]

Answer:

Explanation:

Given that,

Small wheel applied force

F₁ = 50N

Small wheel radius

r₁ = 18cm

Bigger wheel radius.

r₂ = 29cm

Bigger wheel applied force

F₂ =?

Since the combination of those forces did not cause the wheel to rotate,

Then, Στ = 0

F₁•r₁ —F₂•r₂ =

50×18 — 29F₂ = 0

900 = 29F₂

F₂ = 900 / 29

F₂ = 31.03 N

The pulling force applied at the larger wheel is 31.03N

8 0
4 years ago
Which statement regarding the “Evaporation” lab is most accurate?
Sladkaya [172]
Substances evaporate at different rates
4 0
4 years ago
Read 2 more answers
Two point charges q1 = 4. 0 µc and q2 = -8. 0 µc are placed along the x-axis at x1 = 0 m and x2 = 0. 20 m, respectively. What is
scoundrel [369]

The electric potential energy of this system of charges will be +1.44 J. Option E is correct.

<h3>What is the electric potential energy ?</h3>

Electric potential energy stands for the energy that is required to displace a charge in against an electric field.

Given data;

q₁ = 4. 0 µc

q₂ = -8. 0 µc

D(distance between charges) = 0.2 m

The electric potential energy is found as;

\rm E = \frac{Kq_1q_2}{r} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6}\times (-8.0)\times 10^{-6}}{0.2} \\\\ E=+1.44 J

The electric potential energy of this system of charges will be +1.44 J.

Hence,option E is correct.

To learn more about the electric potential energy refer:

brainly.com/question/12645463

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5 0
2 years ago
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