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2 years ago

10

Manganese-52 has a half-life of 6 days. How many days would a scientist have to wait for the radioactivity to be 12.5% the start

ing amount?

2 answers:

Dahasolnce [82]2 years ago

5 0

Answer:

18 Days

Explanation:

sineoko [7]2 years ago

4 0

Answer:

Let N = N0 where N0 is the number of atoms originally present.

In 6 days N = N0 / 2

In 12 days N = N0 / 4

In 18 days N = N0 / 8 = .125 N0

So it would take 18 days.

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Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'

nignag [31]

The position of the particle is given by:

x(t) = t³ - 12t² + 21t - 9

Differentiate x(t) with respect to t to find the velocity x'(t):

x'(t) = 3t² - 24t + 21

Differentiate x'(t) with respect to t to find the acceleration x''(t):

x''(t) = 6t - 24

5 0

2 years ago

What force does it take to accelerate a 9.2 kg object 7.0 m/s^2?

Ulleksa [173]

Answer:

<h2>64.4 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 9.2 kg

acceleration = 7 m/s²

We have

force = 9.2 × 7 = 64.4

We have the final answer as

<h3>64.4 N</h3>

Hope this helps you

5 0

2 years ago

Would this one be correct?(C.)

BaLLatris [955]

No. The correct one would be D .

5 0

2 years ago

This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The mag

Dmitry [639]

Answer:

Part a)

$F = 135.7 N$

Part b)

$F = 62.5 N$

Explanation:

Part a)

If block is sliding up then net force must be zero and friction will be in opposite to the direction of motion of the block

$Fcos\theta = mg + F_f$

$Fsin\theta = F_n$

so we have

$Fcos\theta = mg + \mu(Fsin\theta)$

$F(cos\theta - \mu sin\theta) = mg$

$F = \frac{mg}{cos\theta - \mu sin\theta}$

$F = \frac{55}{cos50 - 0.310(sin50)}$

$F = 135.7 N$

Part b)

If block is sliding down then net force must be zero and friction will be in opposite to the direction of motion of the block

$Fcos\theta = mg - F_f$

$Fsin\theta = F_n$

so we have

$Fcos\theta = mg - \mu(Fsin\theta)$

$F(cos\theta + \mu sin\theta) = mg$

$F = \frac{mg}{cos\theta + \mu sin\theta}$

$F = \frac{55}{cos50 + 0.310(sin50)}$

$F = 62.5 N$

6 0

3 years ago

Determine the kinetic energy of 1000-kg roller coaster car that is moving with speed of 20.0m/s

nevsk [136]

B, i got the same question

7 0

2 years ago