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Vilka [71]
3 years ago
7

a baseball is pitched with a speed of 35.0m/s. how long does it take the ball to travel 18.4 m from the pitchers mound to home p

late

Physics
1 answer:
Vlad [161]3 years ago
7 0
Given the speed and the distance, to find time you can use the formula speed is equal to distance over time. From there you can manipulate the equation for time to equal the distance divided by speed. Time is equal to 18.4 meters divided by 35m/s which equals 0.526 seconds.

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The head of a rattlesnake can accelerate at 49 m/s2 in striking a victim. If a car could do as well, how long would it take to r
Anettt [7]
<h2>Time taken is 0.459 seconds</h2>

Explanation:

We have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = 81 km/hr = 22.5 m/s    

     Time, t = ?

     Acceleration, a = 49 m/s²

     Substituting

                      v = u + at  

                      22.5 = 0 + 49 x t

                      t = 0.459 seconds

   Time taken is 0.459 seconds

3 0
3 years ago
Gravity can be described as (2 points)
ladessa [460]

Answer:

"the force of attraction between two objects"

Explanation:

According to Newton's Universal Law of Gravitation, gravity is a force of attraction acting between objects that possess mass. The fact that we only observe gravitational attraction (as opposed to repulsion) makes gravity unique among the known forces.

6 0
2 years ago
Which of these is the unit of measure for work?
Anastasy [175]
The SI unit of measure for work, as well as
for all other kinds of energy, is the "joule".
7 0
2 years ago
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we had to drive 150 miles to the hotel we left at 1 p.m. and got there at 4 p.m. what is our average speed
marta [7]
The answer is 50mi/hr
4 0
2 years ago
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Block with mass m =7.6 kg is hung from a vertical spring. when the mass hangs in equilibrium, the spring stretches x = 0.29 m. w
PSYCHO15rus [73]

1) 256.9 N/m

The force applied to the spring is equal to the weight of the block hanging on the spring:

F=mg=(7.6 kg)(9.8 m/s^2)=74.5 N

And the spring constant can be found by using Hook's law, because we know that the displacement caused by this force is x = 0.29 m:

F=kx\\k=\frac{F}{x}=\frac{74.5 N}{0.29 m}=256.9 N/m

2) 1.08 Hz

The angular frequency of oscillation of the spring is given by the formula:

\omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{256.9 N/m}{7.6 kg}}=5.81 rad/s

And the frequency of oscillation is given by:

\omega=2\pi f\\f=\frac{2 \pi}{\omega}=\frac{2\pi}{5.81 rad/s}=1.08 Hz

3) 2.19 m/s

The velocity at time t of the block is given by:

v=v_0 cos (\omega t)

where

v_0 = 4.4 m/s is the initial velocity of the block

\omega=5.81 rad/s is the angular frequency

t is the time

Substituting t=0.36 s, we find the speed of the block at that time:

v(0.36 s)=(4.4 m/s) ( cos ((5.81 rad/s)(0.36 s)) = -2.18 m/s

And the negative sign means that the direction of the velocity is upward (because the initial velocity was downward)

4) 25.6 m/s^2

The maximum acceleration is given by:

a_0 = \omega^2 A

where A is the amplitude of the oscillation.

We can find the amplitude by using the law of conservation of energy: in fact, the kinetic energy at the equilibrium point must be equal to the elastic potential energy at the point of maximum displacement:

K=U\\\frac{1}{2}mv_0^2 = \frac{1}{2}kA^2\\A=\sqrt{\frac{mv_0^2}{k}}=\sqrt{\frac{(7.6 kg)(4.4 m/s)^2}{256.9 N/m}}=0.76 m

So, the maximum acceleration is

a_0 = \omega^2 A=(5.81 rad/s)^2 (0.76 m)=25.6 m/s^2

5) 95.1 N

The magnitude of the net force acting on the block is given by the difference between the weight and the restoring force of the spring:

F=mg-kx

First, we need to find the position x at t=0.36 s, which is given by

x(t)=A sin(\omega t)=(0.76 m)(sin ((5.81 rad/s)(0.36 s))=0.66 m

And so, the net force is

F=(7.6 kg)(9.8 m/s^2)-(256.9 N/m)(0.66 m)=-95.1 N

And the negative sign means the direction of the force is upward.

8 0
2 years ago
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