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Molodets [167]
3 years ago
15

You have an aquarium which holds 2.65 gallons of water and you would like to place it on an antique stand. Before placing the aq

uarium on the stand, as a precaution, you decide to determine the weight of the water in the aquarium. Determine the weight of water you will be placing in the aquarium.
Physics
2 answers:
snow_tiger [21]3 years ago
8 0

Answer:

10.0 kg

Explanation:

1 gallon of water is equal to 3.79 liters of water. Then, 2.65 gallons of water are:

2.65 gal water × (3.79 L water / 1 gal water) = 10.0 L water

The density of water is about 1.00 kg/L. The mass corresponding to 10.0 L of water is:

10.0 L × (1.00 kg/L) = 10.0 kg

The mass of 2.65 gallons of water is 10.0 kg.

qwelly [4]3 years ago
6 0

Answer:

The weight of the water is 10.0 kg

Explanation:

Hi there!!

Since the density of water is 1 g/ml, knowing the volume of water, we can determine its weight. First, let´s convert the unit gallon into liters:

1 gallon = 3.785 l

Then:

2.65 gallons · (3.785 l / 1 gallon) = 10.0 l

Since 1 l = 1000 ml, 10.0 l will be 10000 ml

The density of water is 1 g/ml, then the weight of 10.0 l is 10000 g or 10.0 kg.

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A cheetah can run at a maximum speed 103 km/h and a gazelle can run at a maximum speed of 76.5 km/h. If both animals are running
Katena32 [7]

Answer:

1

 t_a  =  13.49 \  s

2

 The distance is   D = 55.2 \  m    

Explanation:

From the question we are told that

   The maximum speed of the cheetah is  v =  103 \  km/h =  28.61 \  m/s

    The maximum of  gazelle is  u =  76.5 \  km/h =  21.25 \  m/s

     The distance ahead is d =  99.3 \  m

Let  t_a denote the time which the cheetah catches the gazelle

Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is

           v* t_a = d +  u* t_a

=>          28.61 t_a = 99.3 +  21.25t_a

=>          7.36 t_a = 99.3

=>         t_a  =  13.49 \  s

Now at t =  7.5 s  

             7.5 v = D+  7.5u

=>          28.61 * 7.5  = D +  21.25* 7.5

=>          7.36 *  7.5 =D

=>         D = 55.2 \  m        

Hence the for the gazelle to escape the cheetah it must be 55.2 m

5 0
3 years ago
Suppose you want to use this human engine to lift a 2.35 kg box from the floor to a tabletop 1.30 m above the floor. How much mu
morpeh [17]

Answer:

The increase in the gravitational potential energy is 29.93 joules.

Explanation:

Given that,

Mass of the box, m = 2.35 kg

It is lifted from the floor to a tabletop 1.30 m above the floor, h = 1.3 m

We need to find the increase the gravitational potential energy. Initial it will placed at ground i.e. its initial gravitational potential is equal to 0. The increase in the gravitational potential energy is given by :

U=mgh

U=2.35\ kg\times 9.8\ m/s^2\times 1.3\ m

U = 29.93 Joules

So, the increase in the gravitational potential energy is 29.93 joules. Hence, this is the required solution.

6 0
3 years ago
What are 3 artificial and 2 natural sources of electromagnetic radiation?
KatRina [158]

Answer: its b bro

Explanation:

ajafa'jfbA'FJ

8 0
3 years ago
Seema knows the mass of a basketball. What other information is needed to find the ball’s potential energy?
adelina 88 [10]

Potential energy can be found using this formula:

PE= m * g * h

where:

PE= potential energy

m=mass

g=gravitational acceleration constant (9.8 m/s^2)

h= height

So your answer is height because you also use the gravitational constant.

7 0
3 years ago
A capacitor with a very large capacitance is in series with a capacitor that has a very small capacitance. what can we say about
Misha Larkins [42]
<span>A capacitor with a very large capacitance is in series with a capacitor
that has a very small capacitance.

The capacitance of the series combination is slightly smaller than the
capacitance of the small capacitor. (choice-C)

The capacitance of a series combination is

             1 / (1/A + 1/B + 1/C + 1/D + .....) .

If you wisk, fold, knead, and mash that expression for a while,
you find that for only two capacitors in series, (or 2 resistors or
two inductors in parallel), the combination is   

             (product of the 2 individuals) / (sum of the individuals)  .

In this problem, we have a humongous one and a tiny one.
Let's call them  1000  and  1 .
Then the series combination is

           (1000 x 1) / (1000 + 1)

        =       (1000) / (1001)

        =         0.999 000 999 . . . 

which is smaller than the smaller individual.

It'll always be that way.   </span>
5 0
3 years ago
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