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Molodets [167]
3 years ago
15

You have an aquarium which holds 2.65 gallons of water and you would like to place it on an antique stand. Before placing the aq

uarium on the stand, as a precaution, you decide to determine the weight of the water in the aquarium. Determine the weight of water you will be placing in the aquarium.
Physics
2 answers:
snow_tiger [21]3 years ago
8 0

Answer:

10.0 kg

Explanation:

1 gallon of water is equal to 3.79 liters of water. Then, 2.65 gallons of water are:

2.65 gal water × (3.79 L water / 1 gal water) = 10.0 L water

The density of water is about 1.00 kg/L. The mass corresponding to 10.0 L of water is:

10.0 L × (1.00 kg/L) = 10.0 kg

The mass of 2.65 gallons of water is 10.0 kg.

qwelly [4]3 years ago
6 0

Answer:

The weight of the water is 10.0 kg

Explanation:

Hi there!!

Since the density of water is 1 g/ml, knowing the volume of water, we can determine its weight. First, let´s convert the unit gallon into liters:

1 gallon = 3.785 l

Then:

2.65 gallons · (3.785 l / 1 gallon) = 10.0 l

Since 1 l = 1000 ml, 10.0 l will be 10000 ml

The density of water is 1 g/ml, then the weight of 10.0 l is 10000 g or 10.0 kg.

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A circular hole in an aluminum plate is 2.739 cm in diameter at 0.000°C. What is the change in its diameter when the temperature
prisoha [69]

Answer:

L = 2.746 cm

Explanation:

As we know that thermal expansion coefficient of aluminium is given as

\alpha = 24 \times 10^{-6} per ^oC

now we also know that after thermal expansion the final length is given as

L = L_o(1 + \alpha \Delta T)

here we know that

L_o = 2.739 cm

\alpha = 24 \times 10^{-6}

\Delta T = 108 - 0= 108^oC

now we will have

L = 2.739(1 + 24 \times 10^{-6} (108))

L = 2.746 cm

3 0
3 years ago
What unit is used for the value of G in Newton's Law of Universal<br> Gravitation?<br> *
Helga [31]

Answer:

In SI units, its value is approximately 6.674×10−11 m3⋅kg−1⋅s−2. The modern notation of Newton's law involving G was introduced in the 1890s by C. V. Boys. The first implicit measurement with an accuracy within about 1% is attributed to Henry Cavendish in a 1798 experiment.

Explanation:

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3 0
2 years ago
PLEASE Please HELP ME...
cupoosta [38]

Answer:

girl this easy ask yo teacher for help lol

7 0
3 years ago
Dwayne ‘The Rock’ Johnson needs to escape from the fourth floor of a burning building (in a movie). He ties a rope around his wa
ZanzabumX [31]

Answer:

Final Speed of Dwayne 'The Rock' Johnson = 15.812 m/s

Explanation:

Let's start out with finding the force acting downwards because of the mass of 'The Rock':

Dwayne 'The Rock' Johnson: 118kg x 9.81m/s = 1157.58 N

Now the problem also states that the kinetic friction of the desk in this problem is 370 N

Since the pulley is smooth, the weight of Dwayne Johnson being transferred fully, and pulls the desk with a force of 1157.58 N. The frictional force of the desk is resisting this motion by a force of 370 N. Subtracting both forces we get the resultant force on the desk to be: 1157.58 - 370 = 787.58 N

Now lets use F = ma to calculate for the acceleration of the desk:

787.58 = 63 x acceleration

acceleration = 12.501 m/s

Finally, we can use the motion equation:

v^2 - u^2 = 2*a*s

here u = 0 m/s (since initial speed of the desk is 0)

a = 12.501 m/s

and s = 10 m

Solving this we get:

v^2 - 0 = 2 * 12.501 * 10

v = 15.812 m/s

Since the desk and Mr. Dwayne Johnson are connected by a taught rope, they are travelling at the same speed. Thus, Dwayne also travels at            15.812 m/s when the desk reaches the window.

5 0
3 years ago
How much power is needed to lift a 20-kg object to a height of 4.0 m in 2.5 seconds?
4vir4ik [10]

Answer:

313.92w

Explanation:

Formula for power:

P=W/∆t = Fv

Givens:

m=20kg

∆y=4.0m

∆t=2.5s

a=9.81m/s²

In order to find power, we first need to solve for work.

W=Fd (force*displacement), f=mg

W=mg∆y

W=(20kg)(9.81m/s²)(4.0m)

W=784.8J

P=W/∆t

P=784.8J/2.5s

P=313.92 watts

5 0
3 years ago
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