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ExtremeBDS [4]
3 years ago
11

A motorcycle has a constant acceleration of 2.5 meters per second squared

Physics
1 answer:
pshichka [43]3 years ago
7 0

Answer:

given \\ accelaration (a)= 2.5 \frac{m}{ {s}^{2} }  \\ initial \: velocity(u) = 21 \frac{m}{s}  \\ final \: velocity(v) = 31 \frac{m}{s}  \\ we \: want \: find \: time \\ newtons \: equation \: of \: motion \: v = u + at \\ 31 = 21 + 2.5 \times t \\ 31 - 21 = 2.5t \\ 10 = 2.5t \\  \frac{10}{2.5}  = t \\ t = 4sec

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A 26-g steel-jacketed bullet is fired with a velocity of 630 m/s toward a steel plate and ricochets along path CD with a velocit
Alecsey [184]

Answer:

  F = - 3.53 10⁵ N

Explanation:

This problem must be solved using the relationship between momentum and the amount of movement.

          I = F t = Δp

To find the time we use that the average speed in the contact is constant (v = 600m / s), let's use the uniform movement ratio

        v = d / t

        t = d / v

Reduce SI system

          m = 26 g ( 1 kg/1000g) = 26 10⁻³ kg

          d = 50 mm ( 1m/ 1000 mm) = 50 10⁻³ m

Let's calculate

         t = 50 10⁻³ / 600

         t = 8.33 10⁻⁵ s

With this value we use the momentum and momentum relationship

        F t = m v - m v₀

As the bullet bounces the speed sign after the crash is negative

       F = m (v-vo) / t

       F = 26 10⁻³ (-500 - 630) / 8.33 10⁻⁵

       F = - 3.53 10⁵ N

The negative sign indicates that the force is exerted against the bullet

5 0
3 years ago
If the speed of an object in uniform circular motion is constant and the radial distance is doubled, by what factor does the mag
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Why are the freezing points of water and the melting point the same
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8 0
3 years ago
Natalie accelerate her skateboard along a straight path from 0 m/s to 4.0 m/s in 2.5 s. find her average acceleration
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Acceleration=(speed end - speed start)/ time
Data:
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Answer: the acceleration would be 1.6 m/s²
8 0
3 years ago
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