A motorcycle has a constant acceleration of 2.5 meters per second squared

Physics

1 answer:

pshichka [43]3 years ago

7 0

Answer:

$given \\ accelaration (a)= 2.5 \frac{m}{ {s}^{2} } \\ initial \: velocity(u) = 21 \frac{m}{s} \\ final \: velocity(v) = 31 \frac{m}{s} \\ we \: want \: find \: time \\ newtons \: equation \: of \: motion \: v = u + at \\ 31 = 21 + 2.5 \times t \\ 31 - 21 = 2.5t \\ 10 = 2.5t \\ \frac{10}{2.5} = t \\ t = 4sec$

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2 years ago

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Answer:

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