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AURORKA [14]
3 years ago
6

Determine the shape around the atoms in ethambutol

Chemistry
1 answer:
andrezito [222]3 years ago
5 0

Answer:

             The structure of Ethambutol is attached below. As it can be seen in structure that there are three different atoms which can act as a central atom and hence, can make a geometrical shape. These three atoms are;

(i) Carbon (Tetrahedral):

                Each carbon atom in this compound is Sp³ hybridized because there is no double or triple bond in this compound. So, according to VSEPR theory the four bonded atoms will keep a maximum distance from each other to experience less repulsion. Therefore, the bond angle about carbon atom will be 109.5° and the shape will be Tetrahedral.

(ii) Nitrogen (Trigonal Pyramidal):

                 There are two atoms of Nitrogen in this compound. These Nitrogen atoms are bonded to three atoms. Also, it has one lone pair of electron. This pair of electron will cause the the bond between the atoms to decrease due to more repulsion hence making the bond angle less than 109.5° and giving a Trigonal Pyramidal shape.

(iii) Oxygen (Bent / Angular):

                 The two oxygen atoms are bonded to two atoms and contain two lone pair of electrons, hence, more repulsion and more small angle i.e. 104° giving a bent or angular shape.

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Answer:

Enthalpy change = 74.36 kJ

Explanation:

Enthalpy change is defines as the heat absorbed or evolved during a chemical reaction at constant pressure and volume

Reaction:

H2O(l) --> H2O(g)

DHr = mCsDT

Where m is the mass of water

Cs is the specific heat capacity

DT is the temperature difference

= 31.6 * 4.18 * (25 - 3.2)

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DHvap = 44kJ/mol

Moles of water = mass/molecular weight

Molecular weight = (1*2) + 16

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DHvap = 44 * 1.756

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DH = DHproduct - DHreactant

DHproduct = DHvap = 77.24kJ

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Enthalpy change = 74.36 kJ

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How much heat (in kJ k J ) is evolved in converting 2.00 mol m o l of steam at 135 ∘C ∘ C to ice at -42 ∘C ∘ C ? The heat capaci
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The total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

<h3>Heat evolved in converting the steam to ice</h3>

The total heat evolved is calculated as follows;

Q(tot) = Q1(steam to boiling point) + Q2(boiling point to ice) +Q3(freezing to -42 ⁰C)

where;

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Q = = mcΔθ

where;

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  • c is specific heat capacity,
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Q(tot) = 2(18)(2.01)(100 - 135) + 2(18)(2.01)(0 - 100) + 2(18)(2.09)(-42 - 0)

Q(tot) = -12,928.68 J

Thus, the total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

Learn more about heat here: brainly.com/question/13439286

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