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worty [1.4K]
3 years ago
12

If 3.5 paper clips = 1.0 pencils and your paper is 1.5 pencils long, how many paper clips long is your paper?

Physics
1 answer:
Andrews [41]3 years ago
6 0
\bf \begin{array}{ccll}
paperclips&pencils\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
3.5&1.0\\
p&1.5
\end{array}\implies \cfrac{3.5}{p}=\cfrac{1.0}{1.5}\implies \cfrac{3.5\cdot 1.5}{1}=p
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A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an a
lions [1.4K]

Answer:

Approximately 4.61\times 10^{3}\; {\rm N} upwards (assuming that g = 9.81\; {\rm m\cdot s^{-2}}.)

Explanation:

External forces on this astronaut:

  • Weight (gravitational attraction) from the earth (downwards,) and
  • Normal force from the floor (upwards.)

Let (\text{normal force}) denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:

\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}.

Let m denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be (\text{weight}) = m\, g.

Let a denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be (\text{net force}) = m\, a.

Rearrange \begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned} to obtain an expression for the magnitude of the normal force on this astronaut:

\begin{aligned}(\text{normal force}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= m\, (a + g) \\ &= 80.9\; {\rm kg} \times (47.2\; {\rm m\cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 4.61 \times 10^{3}\; {\rm N}\end{aligned}.

3 0
2 years ago
II) A 0.40-kg ball, attached to the end of a horizontal ord, is rotated in a circle of radius 1.3 m on a friction- less horizont
Lostsunrise [7]

Hi there!

In this instance, the object spinning in a horizontal circle will experience a net force in the horizontal direction due to tension.

The net force is equivalent to the centripetal force, so:

∑F = T

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Solve for v:

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v = 13.96 m/s

3 0
2 years ago
Find the frequency of a wave produced by a generator that emits 100 pulses in 2.0 s.
kobusy [5.1K]

The frequency of the wave is 50 Hz

Explanation:

The frequency of the wave is defined as the number of cycles per second of the wave:

f=\frac{N}{t}

where

N is the number of cycles completed in a time t.

Frequency is measured in Hertz (Hz).

In this problems, the wave has

N = 100 pulses

in

t = 2.0 s

Therefore, its frequency is

f=\frac{100}{2.0}=50 Hz

Learn more about waves and frequency here:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

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3 years ago
Which of the following concepts helps explain the modern technology used in 3D films?
stealth61 [152]

Answer:

a.

Explanation:

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Answer: The magnitude of force per length that each wire exert on the other wire is 2.67×10^-5 N/m.

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