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Flura [38]
3 years ago
10

Modern wind turbines are larger than they appear, and despite their apparently lazy motion, the speed of the blades tips can be

quite high-many times higher than the wind speed. A turbine has blades 59m long that spin at13rpm .
At the tip of a blade, what is the speed?
At the tip of a blade, what is the centripetal acceleration?
A big dog has a torso that is approximately circular, with a radius of 16cm . At the midpoint of a shake, the dog's fur is moving at a remarkable 2.5m/s .
What force is required to keep a 10 mg water droplet moving in this circular arc?
What is the ratio of this force to the weight of a droplet?
Physics
1 answer:
VMariaS [17]3 years ago
6 0

Answer:

speed and acceleration of the turbine V = 80.24 m/s   and a = 109.1 m/s²

Explanation:

The wind turbine describes a circular motion, with constant angular velocity, we can find the speed with the equation

                     V = x / t

Where x is the distance traveled which is the length of the circle (X = 2πr) and time is the time in a revolution, which in this case is called the period

                    t = 60/13  

                    t = 4.62 s

                    x = 2 p1 59

                    x = 370.71 m

                    V = 370.1 / 4.62

                    V = 80.24 m / s

The centripetal acceleration is given by the equation

                   a = V² / r

                   a = 80.24²/59

                   a = 109.1 m / s²

The second part of the exercise seems totally independent

The dog r = 16cm with a speed of 2.5 m/s, ask us the centripetal force

                  F = m a

                  F = m (v² / r)

                  m = 10 mg (1g / 1000mg) 1 Kg / 1000 g) = 1 10⁻⁵ Kg

                  r = 16 cm (1m / 100cm) = 16 10⁻² m

         

                 F = 1 10⁻⁵ 2.5²/16 10⁻²

                 F = 3.91 10⁻² N

Let's calculate the relationship between the force and the weight of the drop

                 F / W = 3.91 10⁻² (1 10⁻⁵ 9.8)

                 F / W = 3.99 10 ²

See that the force of the shake is approximately 400 times greater than the weight of the drop

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3 0
3 years ago
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A phonograph record 0.15 m in its radius rotates 18 times per 90 seconds what is the frequency?
ioda

Answer:

The frequency of the phonograph record is 0.2 Hz

Explanation:

The frequency of an object moving in uniform circular motion is the number of completed cycles the object makes in a specified time period

The given parameters of the phonograph record are;

The radius of the record = 0.15 m

The number of times the phonograph record rotates, n = 18 times

The time it takes the phonograph record to rotate the 18 times, t = 90 seconds

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2 years ago
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The current in a wire varies with time according to the relationship 1=55A−(0.65A/s2)t2. (a) How many coulombs of charge pass a
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Answer:

(A) Q = 321.1C (B) I = 42.8A

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(a)Given I = 55A−(0.65A/s2)t²

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