Answer:
speed and acceleration of the turbine V = 80.24 m/s and a = 109.1 m/s²
Explanation:
The wind turbine describes a circular motion, with constant angular velocity, we can find the speed with the equation
V = x / t
Where x is the distance traveled which is the length of the circle (X = 2πr) and time is the time in a revolution, which in this case is called the period
t = 60/13
t = 4.62 s
x = 2 p1 59
x = 370.71 m
V = 370.1 / 4.62
V = 80.24 m / s
The centripetal acceleration is given by the equation
a = V² / r
a = 80.24²/59
a = 109.1 m / s²
The second part of the exercise seems totally independent
The dog r = 16cm with a speed of 2.5 m/s, ask us the centripetal force
F = m a
F = m (v² / r)
m = 10 mg (1g / 1000mg) 1 Kg / 1000 g) = 1 10⁻⁵ Kg
r = 16 cm (1m / 100cm) = 16 10⁻² m
F = 1 10⁻⁵ 2.5²/16 10⁻²
F = 3.91 10⁻² N
Let's calculate the relationship between the force and the weight of the drop
F / W = 3.91 10⁻² (1 10⁻⁵ 9.8)
F / W = 3.99 10
²
See that the force of the shake is approximately 400 times greater than the weight of the drop
