A 6.8 kg bowling ball and 7.4 kg bowling ball rest on a rack 0.74 m apart. What is the force of gravity pulling each ball toward
1 answer:
The gravitational force between the two balls is
Explanation:
The magnitude of the gravitational force between two objects is given by:
where :
is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the objects
For the balls in this problem, we have
r = 0.74 m
Substituting into the equation, we find the gravitational force between the two balls:
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Answer:
The magnitude of the electric field be 171.76 N/C so that the electron misses the plate.
Explanation:
As data is incomplete here, so by seeing the complete question from the search the data is
vx_0=1.1 x 10^6
ax=0 As acceleration is zero in the horizontal axis so
Equation of motion in horizontal direction is given as
Now for the vertical distance
vy_o=0
than the equation of motion becomes
Now using this acceleration the value of electric field is calculated as
Here a is calculated above, m is the mass of electron while q is the charge of electron, substituting values in the equation
So the magnitude of the electric field be 171.76 N/C so that the electron misses the plate.
Answer:
72 volts.
Explanation:
To solve this, we have to use the Ohm's law.
The ohm's law tells us that the voltage drop of a resistor is directly proportional to the current applied to the conductor.
in this case the current is 1.8 amps and the resistor is 40 ohm
so
.