A 3.0 g aluminum foil ball with a charge of 3.0×10−9C hangs freely from a 1.4 m-long thread. What angle with the vertical the eq
1 answer:
Answer:
0 degree
Explanation:
Mass of aluminium foil=m=3 g=
1 kg=1000 g
Length of thread=l=1.4 m
We have to find the angle made by the string with the vertical equilibrium position.
The ball hang freely therefore, there is no field present.
The angle made by equilibrium position of the string with the vertical is zero because it is influenced under the acceleration due to gravity of earth and equilibrium position lies along the vertical axis.
Hence, the angle made by the equilibrium position of the string =0 degree
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Answer:
The work function ϕ of the metal = 53.4196 x 10⁻¹⁶ J
Explanation:
When light is incident on a photoelectric material like metal, photoelectrons are emitted from the surface of the metal. This process is called photoelectric effect.
The relationship between the maximum kinetic energy () of the photoelectrons to the frequency of the absorbed photons (f) and the threshold frequency (f₀) of the photoemissive metal surface is:
= h(f − f₀)
= hf - hf₀
E is the energy of the absorbed photons: E = hf
ϕ is the work function of the surface: ϕ = hf₀
= E - ϕ
Frequency f = 8.12×10¹⁸ Hz
Maximum kinetic energy = 4.16×10⁻¹⁷ J
Speed of light c = 3 x 10⁸ m/s
Planck's constant h = 6.63 × 10⁻³⁴ Js
E = hf = 6.63 × 10⁻³⁴ x 8.12×10¹⁸
E = 53.8356 x 10⁻¹⁶ J
from = E - ϕ ;
ϕ = E -
ϕ = 53.8356 x 10⁻¹⁶ - 4.16×10⁻¹⁷
ϕ = 53.4196 x 10⁻¹⁶ J
The work function of the metal ϕ = 53.4196 x 10⁻¹⁶ J