All categories

3 years ago

What is the unit of G in the F=Gm1m2/r^2

Physics

2 answers:

Sloan [31]3 years ago

7 0

Where: F is the force between the masses; G is the gravitational constant (6.674×10−11 N. (m/kg)2);

kobusy [5.1K]3 years ago

6 0

G
has the SI units
m
3
k
g
⋅
s
2

You might be interested in

Remaining Time: 1 hour, 49 minutes, 34 seconds.

ohaa [14]

Explanation:

i think C . it is twice the size of the object

4 0

3 years ago

How much of the matter in the universe is comprised of atoms?

Deffense [45]

Explanation:

Atoms are the components of ordinary matter, also called baryonic matter, which only represents 4% of the universe, while the remaining 96% would be formed by what is known as dark matter and dark energy which constitute two of the unsolved problems in physics.

4 0

2 years ago

Read 2 more answers

2013 Indianapolis 500 champion Tony Kanaan holds his hand out of his IndyCar while driving through still air with standard atmos

Citrus2011 [14]

Answer:

(a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

All answer are reasonable.

Explanation:

Given that,

Speed v₁= 60 mph

Speed v₂ = 225 mph

Speed v₃ = 235 mph

(a). We need to calculate the maximum pressure on his hand

Using equation of pressure

$P_{1}=P+\dfrac{1}{2}\rho v^2+\rho gh$

there, no vertical movement

So, on neglect of height term

$P_{1}=P+\dfrac{1}{2}\rho v_{1}^2$

Where, P= atmospheric pressure

$\rho$ = air density

v = speed

Put the value in the equation

$P_{1}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(60\times1.4667)^2)$

$P_{1}=2126.0\ lb/ft^2$

$P_{1}=\dfrac{2126.0}{144}$

$P_{1}= 14.76\ psi$

(b). Speed v₂ = 225 mph

We need to calculate the maximum pressure on his hand

Using equation of pressure

$P_{2}=P+\dfrac{1}{2}\rho v_{2}^2$

Put the value in the equation

$P_{2}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(225\times1.4667)^2)$

$P_{2}=2246.17\ lb/ft^2$

$P_{2}=\dfrac{2246.17}{144}$

$P_{2}= 15.59\ psi$

(c). Speed v₃ = 235 mph

We need to calculate the maximum pressure on his hand

Using equation of pressure

$P_{3}=P+\dfrac{1}{2}\rho v_{3}^2$

Put the value in the equation

$P_{3}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(235\times1.4667)^2)$

$P_{3}=2257.93\ lb/ft^2$

$P_{3}=\dfrac{2257.93}{144}$

$P_{3}= 15.68\ psi$

According to bernoulli's equation,

If the car increases the velocity the the pressure on the surface of the driver's hand increases.

The pressure from P₁ to P₃ are all near the value of one atmosphere.

So, the pressure difference of one atmosphere is not enough to break the driver's hand.

Hence, (a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

All answer are reasonable.

5 0

3 years ago

You are tasked with calibrating the springs for a pinball machine. Your method of testing the springs is by attaching masses ont

choli [55]

Answer:

$490.5\ \text{N/m}$

Explanation:

m = Mass attached to spring = 14 kg

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

x = Displacement of spring = $78-50=28\ \text{cm}$

k = Spring constant

The force balance of the system is given by

$kx=mg\\\Rightarrow k=\dfrac{mg}{x}\\\Rightarrow k=\dfrac{14\times 9.81}{0.28}\\\Rightarrow k=490.5\ \text{N/m}$

The spring constant for that spring is $490.5\ \text{N/m}$ .

6 0

3 years ago

How much of the Moon is always illuminated one time? Explain your answer.

Natalija [7]

Answer:

50% of it .

Explanation:

50% of it is illuminated by the Sun.

6 0

3 years ago

What is the unit of G in the F=Gm1m2/r^2​

What is the unit of G in the F=Gm1m2/r^2