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inysia [295]
2 years ago
8

Asp plz do right now

Chemistry
1 answer:
goldenfox [79]2 years ago
3 0
You should make dots and join the line to make a graph use the tov above that will help
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Sulfuric acid (H2SO4) is a very strong diprotic acid. If 0.054 moles of sulfuric acid is mixed with water to make 667 milliliter
Nikitich [7]
As, using formula.........0.054/(.667/18)
=.o54/.037
=1.45 approx

so the answer
4 0
2 years ago
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During a chemical reaction, an iron atom became the ion Fe2+. What happened to the iron atom?
Mariana [72]
The Iron atom lost two electrons to become the Fe2+ ion. This is referred to as oxidation.
5 0
3 years ago
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What is the velocity of a wave traveling north with a frequency of 75 hertz and a wavelength of
Vanyuwa [196]

Answer:

v = 450 m/s

Explanation:

Given data:

Frequency = 75 Hz

Wavelength = 6 m

Velocity = ?

Solution:

Velocity is the product of frequency and wavelength.

v = f × λ

v = 75 Hz ×  6 m

Hz = s⁻¹

v = 75  s⁻¹  ×  6 m

v = 450 m/s

3 0
3 years ago
explain how to determine the number of atoms, cations, and anions in ionic compounds. use an example to explain. ​
Damm [24]

Answer:

use coefficients and subscripts to determine how many atoms are in a compound. If there is no subscript or coefficient, assume it is 1. If there is a coefficient, multiply it with the subscripts. For counting cations and anions, determine first which is the anion and cation (anion = nonmetal, cation = metal), then count the number of that ion.

Example:

NaCl

one atom of Na, one atom of Cl. Since Na is a metal, it is a cation. Cl is a nonmetal, so it is an anion.

2CaCl2

2 atoms of Ca, 4 atoms of Cl. There are 2 cations, since Na is a metal, and 4 anions since Cl is a nonmetal

8 0
2 years ago
PLEASE HELP!!!!!!!
dsp73

Answer: 1. 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

2. 3 moles of CuCl_2 : 2 moles of Al

3. 0.33 moles of CuCl_2 : 0.92 moles of Al

4. CuCl_2 is the limiting reagent and Al is the excess reagent.

5. Theoretical yield of AlCl_3 is 29.3 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles

\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles

The balanced chemical equation is:

2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu  

According to stoichiometry :

3 moles of CuCl_2 require = 2 moles of Al

Thus 0.33 moles of CuCl_2 will require=\frac{2}{3}\times 0.33=0.22moles  of Al

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Al is the excess reagent.

As 3 moles of CuCl_2 give = 2 moles of AlCl_3

Thus 0.33 moles of CuCl_2 give =\frac{2}{3}\times 0.33=0.22moles  of AlCl_3

Theoretical yield of AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3

Thus 29.3 g of aluminium chloride is formed.

5 0
2 years ago
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