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2 years ago

Chemistry help!

Chemistry

1 answer:

Delvig [45]2 years ago

3 0

Answer: C, B, A

Explanation:

C is the initial solution, because naoh has not been added yet

B is the midpoint of the titration. naoh has been added to the solution, but it has not fully reacted yet. You can tell that this one is the midpoint because there is still HF- in the diagram, which is not one of the products formed in the reaction.

A is the endpoint because the diagram shows that all products are fully formed. There is an increased amount of Na+ and H2O in the diagram and no HF- left.

PS. I tested this answer on the concentration of acetic acid post-lab (from mcgraw hill) earlier today and it said this was the right answer :) hope this helps

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Hurry please!

Pani-rosa [81]

Answer : The mass of of water present in the jar is, 298.79 g

Solution : Given,

Mass of barium nitrate = 27 g

The solubility of barium nitrate at $20^oC$ is 9.02 gram per 100 ml of water.

As, 9.02 gram of barium nitrate present in 100 ml of water

So, 27 gram of barium nitrate present in $\frac{27g}{9.02g}\times 100ml=299.33ml$ of water

The volume of water is 299.33 ml.

As we know that the density of water at $20^oC$ is 0.9982 g/ml

Now we have to calculate the mass of water.

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}$

$\text{Mass of water}=(0.9982g/ml)\times (299.33ml)=298.79g$

Therefore, the mass of of water present in the jar is, 298.79 g

5 0

3 years ago

Acetylene gas, C2H2, can be produced by the reaction of calcium carbide and water. CaC2(s) + 2H2O(l) --> C2H2(g) + Ca(OH)2(aq

nekit [7.7K]

Answer:

1.0 L

Explanation:

Given that:-

Mass of $CaC_2$ = $2.54\ g$

Molar mass of $CaC_2$ = 64.099 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{2.54\ g}{64.099\ g/mol}$

$Moles_{CaC_2}= 0.0396\ mol$

According to the given reaction:-

$CaC_2_{(s)} + 2H_2O_{(l)}\rightarrow C_2H_2_{(g)} + Ca(OH)_2_{(aq)}$

1 mole of $CaC_2$ on reaction forms 1 mole of $C_2H_2$

0.0396 mole of $CaC_2$ on reaction forms 0.0396 mole of $C_2H_2$

Moles of $C_2H_2$ = 0.0396 moles

Considering ideal gas equation as:-

$PV=nRT$

where,

P = pressure of the gas = 742 mmHg

V = Volume of the gas = ?

T = Temperature of the gas = $26^oC=[26+273]K=299K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles = 0.0396 moles

Putting values in above equation, we get:

$742mmHg\times V=0.0396 mole\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 299K\\\\V=\frac{0.0396\times 62.3637\times 299}{742}\ L=1.0\ L$

<u>1.0 L of acetylene can be produced from 2.54 g $CaC_2$ .</u>

4 0

3 years ago

a pure substance that cannot be broken down into any other substances by chemicals or physical mean is a

Nat2105 [25]

It is a element.

Pure substances includes either compunds, or elements. Elements are the simplest form of pure substance, they only consist of one kind of atoms. On the other hand, compounds contains two or more elements that are chemically combined together. Although you couldn't separate a compound by physical methods like filtration, but you can seperate them with chemical methods such as heating or electrolysis, using electricity.

Therefore, since compounds can be broken down eventually, so, the answer will be element.

7 0

3 years ago

A 50.0-g sample of liquid water at 25.0°C is mixed with 35.0 g of water at 89.0°

Scorpion4ik [409]

390 because im cool and awsome

5 0

3 years ago

Why is the Ring of Fire a very geologically active part of the earth?

VikaD [51]

Answer:

Explanation:

transform bounderies

5 0

3 years ago