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patriot [66]
3 years ago
13

Read the information on Hydrochloric Acid. List four ways you can avoid injury while using HCl and three steps you would take in

case of an accidental exposure to HCl.
Chemistry
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer:

Find the list and explanation below.

Explanation:

Hydrochloric acid shortened as HCl is a harmful chemical when not handled properly. Four ways to avoid injury with hydrochloric acid include;

1. Dilution: It is advised to dilute the concentrated hydrochloric acid with a reasonable amount of water so that its corrosive effect can be significantly reduced.

2. Wear a laboratory coat: When working with hydrochloric acid in the laboratory it is always advised to wear a laboratory suit so as to ensure a minimal amount of harm in case of an accident or spillage with the acid.

3. Wear a face shield: It is also important that a face shield is worn while working with the acid to prevent contact with the eyes.

4. Wear a protective rubber glove: The rubber gloves would ensure that there is minimal contact of the acid with the hands.

Three steps to be taken in case of an accidental exposure include;

1. Medical Attention: In serious cases, such as in a case of ingesting the acid, urgent medical help should be sought for immediately.

2. Water: If there is contact with the skin or eye, a lot of water should be used on the affected area, and then medical help obtained.

3. Inhalation of fresh air: In a case whereby the hydrochloric acid was inhaled for a long time, the affected person should try to get some fresh air and if other effects are noticed, urgent medical attention should be gotten.

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Answer:

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Explanation:

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4 years ago
92 grams of ethanol,C2H5OH, is dissolved in 1 liter of solution. Determine the molarity (M)
const2013 [10]

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Explanation:

molarity = moles of solute/liters of solution or M = \frac{mol}{L}

first we have to find our moles of solute (mol), which you can find by dividing the mass of solute by molar mass of solute

mass of solute: 92 g

molar mass of solute: 46.08 g/mol

let's plug it in:

\frac{92 g}{46.08 g/mol} = 1.997 mol

next, we plug it into our original equation:

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URGENT
antoniya [11.8K]

Answer:

a

Explanation:

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