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creativ13 [48]
4 years ago
10

) Any gas exerts a pressure against its surroundings. For example, if you put more gas in a balloon, it exerts more pressure and

expands the balloon. Describe what causes the pressure in a gas, in terms of the fact that molecules of gas are moving.
Chemistry
1 answer:
kolezko [41]4 years ago
8 0

Explanation:

As we know that molecules of a gas move far away from each other because they are held by weak Vander waal forces. So, when a balloon is filled by a gas then molecules of a gas strike at its walls leading to more number of collisions.

This will also lead to more expansion of the balloon. As we know that pressure is the force exerted n per unit area of a substance or object.

Thus, more is the kinetic energy of the molecules of the gas more will be the force exerted by them. Hence, more will be the pressure exerted.  

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Br2(i) would be sealed due to my calculations
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The bronsted-lowry definition views an acid-base reaction as a _____ transfer reaction.
Effectus [21]

The bronsted-lowry definition views an acid-base reaction as a proton transfer reaction.

Johannes Nicolaus Brnsted and Thomas Martin Lowry independently developed the Brnsted-Lowry theory, also known as the proton theory , which states that any compound that can transfer a proton to another compound is an acid, and the compound that accepts the proton is a base.

A proton is a nuclear particle with a unit positive electrical charge; it is denoted by the symbol H+. Similar to how a substance can only act as a base when a acid is present, a substance can only act as an acid when a base is present. Additionally, an acidic material transforms into a basic when it loses a proton.

In addition, when a basic substance obtains a proton, it generates an acid known as the conjugate acid of a base, and when an acidic substance loses a proton, it forms a base known as the conjugate base of an acid.

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1 year ago
A satellite in orbit maintains a constant speed while orbiting around the earth.
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Newton's 2nd Law (Option B)

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7 0
3 years ago
What mass of aluminum sulfate is required to precipitate all of the Ba?? out of 45.0 mL of 0.548 M barium nitrate solution? 3 Ba
Verizon [17]

Answer:

2.82 g

Explanation:

Step 1: Write the balanced precipitation reaction

3 Ba(NO₃)₂ (aq) + Al₂(SO₄)₃ (aq) ⇒ 3 BaSO₄(s) + 2 Al(NO₃)₃(aq)

Step 2: Calculate the reacting moles of Ba(NO₃)₂

45.0 mL (0.0450 L) of 0.548 M Ba(NO₃)₂ react.

0.0450 L × 0.548 mol/L = 0.0247 mol

Step 3: Calculate the moles of Al₂(SO₄)₃ that react with 0.0247 moles of Ba(NO₃)₂

The molar ratio of Ba(NO₃)₂ to Al₂(SO₄)₃ is 3:1. The reacting moles of Al₂(SO₄)₃ are 1/3 × 0.0247 mol = 8.23 × 10⁻³ mol

Step 4: Calculate the mass corresponding to 8.23 × 10⁻³ moles of Al₂(SO₄)₃

The molar mass of Al₂(SO₄)₃ is 342.2 g/mol.

8.23 × 10⁻³ mol × 342.2 g/mol = 2.82 g

5 0
3 years ago
Carbon, hydrogen and ethane each burn exothermically in an excess of air. AHⓇ =-393.7 kJ mol. C(s) + O2(g) → CO2(g) H2(g) + % O2
Salsk061 [2.6K]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 51.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the reaction of carbon and water follows:

2C(s)+2H_2(g)\rightarrow C_2H_4(g) \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_1=-393.7kJ    ( × 2)

(2) H_2+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_2=-285.9kJ     ( × 2)

(3) 2C_2H_4(s)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)    \Delta H_3=-1411kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[2\times \Delta H_1]+[2\times \Delta H_2]+[1\times (-\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(2\times (-393.7))+(2\times (-285.9))+(1\times -(-1411))]=51.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is 51.8 kJ.

6 0
4 years ago
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