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ratelena [41]
1 year ago
11

How do you know the correct number of significant figures to include in an answer?

Chemistry
1 answer:
bogdanovich [222]1 year ago
4 0

Answer:

Explanation:

  1 Non-zero digits are always significant.

  2 Any zeros between two significant digits are significant.

  3 A final zero or trailing zeros in the decimal portion ONLY are significant.

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Is aluminum flammable
VashaNatasha [74]
Yes, aluminum is flammable
3 0
3 years ago
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The Gulf Stream flows along the equator before turning north along Florida’s east coast. How does the Gulf Stream impact Florida
nignag [31]

Answer:

The Gulf Stream is influential on the climate of the Florida peninsula.East winds moving over this warm water move warm air from over the Gulf Stream inland, helping to keep temperatures milder across the state than elsewhere across the Southeastern United States during the winter.

Explanation:

hope this helps!

8 0
2 years ago
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**MEDAL AND FAN** what structural units make up metallic solids?
Margarita [4]
C)

Metallic solids consist of metal ions which are surrounded by delocalized electrons.
8 0
2 years ago
A student weighs out a 6.64 g sample of , transfers it to a 500. mL volumetric flask, adds enough water to dissolve it and then
Vsevolod [243]

Answer:

the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M

Explanation:

Given that :

a student dissolves 6.64 g of CoF₂  into 500 mL of water

volume of the solution(water) = 500 mL = 0.50 L

The standard  molar mass of CoF₂ is 96.93 g/mol

number of moles of CoF₂ = mass of CoF₂/molar mass of CoF₂

number of moles of CoF₂ = 6.64 g/96.93 g/mol

number of moles of CoF₂ = 0.0685 mol

The molarity of any given substance is known to be as the number of moles of solute dissolved in one litre of solution.

Thus ;

Molarity of  cobalt(II) fluoride CoF₂ in the resulting solution is = number of moles / Volume in (L)

Molarity of  cobalt(II) fluoride CoF₂  = 0.0685 mol/ 0.50 L

= 0.137  M

Thus ; the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M

7 0
2 years ago
A 4.00L flask containing Ne at 25 C and 6.00 atm is joined by a valve to an 8.00 L flask Ar at 25 C and 2.00 atm.
timama [110]

Answer:

P=3.33atm

Explanation:

Hello!

In this case, since know the volume, temperature and pressure of the initial containers, we can compute the moles of each gas prior to the opening of the valve as shown below:

n_{Ne}=\frac{6atm*4L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.981molNe\\\\n_{Ar}=\frac{2atm*8L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.654molAr

Next, we add them up to obtain the total moles:

n_T=0.981mol+0.654mol=1.635mol

Now, the total volume:

V_T=4.00L+8.00L=12.00L

Finally, the total pressure is computed by using the ideal gas equation:

P=\frac{1.635mol*0.08206\frac{atm*L}{mol*K}*298.15K}{12.00L}\\\\P=3.33atm

Best regards!

6 0
3 years ago
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