Enthalpy of formation is calculated by subtracting the total enthalpy of formation of the reactants from those of the products. This is called the HESS' LAW.
ΔHrxn = ΔH(products) - ΔH(reactants)
Since the enthalpies are not listed in this item, from reliable sources, the obtained enthalpies of formation are written below.
ΔH(C2H5OH) = -276 kJ/mol
ΔH(O2) = 0 (because O2 is a pure substance)
ΔH(CO2) = -393.5 kJ/mol
ΔH(H2O) = -285.5 kJ/mol
Using the equation above,
ΔHrxn = (2)(-393.5 kJ/mol) + (3)(-285.5 kJ/mol) - (-276 kJ/mol)
ΔHrxn = -1367.5 kJ/mol
<em>Answer: -1367.5 kJ/mol</em>
Answer:
fe3o4+4h2 - 3fe + 4h2o
therefore coefficient is 4
Answer:
The answer to your question is below
Explanation:
Factors that affect the rate of a chemical reaction
- Temperature If the temperature increases the rate of reaction increases.
- Concentration The reaction will move where there less concentration it could be to the reactants of products.
- Particle size The lower the particle size the higher the rate of reaction.
- Catalyst Catalyzers accelerate the rate of reaction
- Pressure The reaction will move where there are fewer molecules.
The chemical properties, chemical reactivity
Question 4: The first one
Question 5: The fourth one
Question 6: The first one
Question 7: The third one
