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3 years ago

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Action that occurs as two or more objects have an

1 answer:

Naya [18.7K]3 years ago

4 0

The action is interaction

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What contribution to atomic theory resulted from albert einstein’s work?

Hatshy [7]

Answer:

Albert Einstein is perhaps most famous for introducing the world to the equation E=mc2. In essence, he discovered that energy and mass are interchangeable, setting the stage for nuclear power—and atomic weapons. His part in the drama of nuclear war may have ended there if not for a simple refrigerator.

Explanation:

Albert Einstein is perhaps most famous for introducing the world to the equation E=mc2. In essence, he discovered that energy and mass are interchangeable, setting the stage for nuclear power—and atomic weapons. His part in the drama of nuclear war may have ended there if not for a simple refrigerator.

8 0

3 years ago

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Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m

koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

$R_{in}$ $= \frac{0.04}{100}*2000$

$R_{in}$ = 0.8

The rate-out

$R_{out}$ = $\frac{A}{6000}*2000$

$R_{out}$ = $\frac{A}{3}$

We can say that:

$\frac{dA}{dt}=$ $0.8-\frac{A}{3}$

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

$\frac{dA}{dt} +\frac{A}{3} =0.8$

Integration of the above linear equation =

$e^{\int\limits \frac {1}{3}dt } =$ $e^{\frac{1}{3}t$

so we have:

$e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A$ $= 0.8e^{\frac{1}{3}t$

$\frac{d}{dt}[e^{\frac{1}{3}t}A]$ $= 0.8e^{\frac{1}{3}t$

$Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C$

∴ $A(t) = 2.4 +Ce^{-\frac{1}{3}t$

Since A(0) = 12

Then;

$12 =2.4 + Ce^{-\frac{1}{3}}(0)$

$C= 12-2.4$

$C =9.6$

Hence;

$A(t) = 2.4 +9.6e^{-\frac{t}{3}}$

$A(0) = 2.4 +9.6e^{-\frac{10}{3}}$

$A(t) = 2.74$

∴ the concentration at 10 minutes is ;

= $\frac{2.74}{6000}*100$ %

= 0.0456667 %

= 0.046% to three decimal places

7 0

3 years ago

Potassium chlorate is a white, crystalline solid. It can be broken down into potassium chloride (a salt)

lions [1.4K]

Answer:

Notice that the number of atoms of

K

and

Cl

are the same on both sides, but the numbers of

O

atoms are not. There are 3

O

atoms on the the left side and 2 on the right. 3 and 2 are factors of 6, so add coefficients so that there are 6

O

atoms on both sides.

2KClO

3

(

s

)

+ heat

→

KCl(s)

+

3O

2

(

g

)

Now the

K

and

Cl

atoms are not balanced. There are 2 of each on the left and 1 of each on the right. Add a coefficient of 2 in front of

KCl

.

2KClO

3

(

s

)

+ heat

→

2KCl(s)

+

3O

2

(

g

)

The equation is now balanced with 2

K

atoms,

7 0

3 years ago

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Is it Nephrons or Kidney or Urine or Urethra

UkoKoshka [18]

Answer:

it's urine option ( C ) .

7 0

4 years ago

1. Calculate the momentum of a 1,500 kg car traveling at 6 m/s.

ziro4ka [17]

Answer:

1. $9000kgm/s$

2. $258,000kgm/s$

Explanation:

1.Momentum is given as the product of mass by velocity of an object.

Momentum, $p=mv$

m=1,500kh, v=6m/s

$p=1500*6\\p=9000kgm/s$

2.Momentum, $p=mv$

m=7800kg, v=30m/s

$p_1=7800*30\\p_1=234,000kgm/s\\$

new mass=7800+800=8600

As mass is increased, so does the resultant velocity as mass is directly proportional to velocity.

$p_2=8600*30\\p_2=258,000kgm/s$

8 0

4 years ago