Molar mass of butane = 12g/mol*4+1g/mol*10=58g/mol
Mass of 2 moles of butane=2mol*58g/mol=116g
2c4h10(g)+13o2(g)->8co2(g)+10h2o(l)
<span>116g 8 moles</span>
<span>3.20g x</span>
116g butane/8moles CO2=3.20g butane/x
x=3.20g butane*8moles CO2/116g butane=0.2207moles CO2
T=23°C=296K
PV=nRT
V=nRT/P=0.2207moles*0.082(atm*dm³/(K/mol))*296K/(1atm)=5.36dm³
Answer:
Whenever the two groups on each end of a carbon-carbon double bond are the same, two diastereomers are possible.
Explanation:
Double bonds are formed when four electrons are shared between two carbon atoms. The second bond is generally known as a pi-bond while the first bond is called a sigma bond.
The presence of a double bond in a compound leads to restricted rotation about the carbon-carbon double bond. Hence the substituents are 'locked' in a particular configuration.
The more substituted a double bond is, the more stable it is according to Saytzeff's Rule.
Due to steric effects, trans alkenes are generally more thermodynamically stable than cis alkenes since trans alkenes have bulky groups oriented apart from each other.
All these are true statements. The answer selected must be the untrue statement.
Answer: between 6.5 and 8.5
Explanation:
As shown in my science book it appears in the ph scale
