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3 years ago

How can you describe the state of equilibrium in a saturated solution that contains undissolved?

Chemistry

1 answer:

lianna [129]3 years ago

5 0

It's supersaturated because the solution can't be saturated any more.

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Now suppose, instead, that 5.678 g of a volatile solute is dissolved in 150.0 g of water. This solute also does not react with w

n200080 [17]

Answer:

59.9 g/mol is the molar mass for the solute

Explanation:

Lowering vapor pressure → ΔP = P° . Xm

P° → Vapor pressure of pure solvent

ΔP = P° - Vapor pressure of solution

Xm = Mole fraction of solute

17.54 Torr - 17.344 Torr = 17.54 Torr . Xm

0.196 Torr / 17.54 Torr = Xm → 0.0112

These are the moles of solute / Total moles

Total moles = Moles of solute + Moles of solvent

We determine the moles of solvent → 150 g . 1mol/ 18 g = 8.33 moles

Now we can make this equation:

0.0112 = Moles of solute / Moles of solute + 8.33 mol

0.0112 Moles of solute + 0.0933 = Moles of solute

0.0933 = Moles of solute - 0.0112 Moles of solute

0.0933 = 0.9888 moles of solute → 0.0933 / 0.9888 = 0.0947 moles

Finally we can determine the molar mass (mol/g)

5.678 g / 0.0947 mol = 59.9 g/mol

4 0

3 years ago

The movement of water across a membrane is termed

katen-ka-za [31]

The answer is diffusion

5 0

3 years ago

Does anyone know how many grams of of fe2o3 react to produce 450 grams of fe

notka56 [123]

Answer:

14.4g

Explanation:

5 0

3 years ago

The balanced equation below shows the products that are formed when pentane (C5H12) is combusted. C5H12 + 8O2 mc029-1.jpg 10CO2

Maru [420]

Answer: The mole ratio of oxygen to pentane for the combustion of pentane is 8 : 1.

Explanation: The given reaction is a type of combustion reaction.

Combustion reaction is a reaction in which a hydrocarbon reacts with oxygen gas to produce water and carbon dioxide gas.

For the reaction of pentane with oxygen, the balanced equation would be:

$C_5H_{12}+8O_2\rightarrow 5CO_2+6H_2O$

In the reaction, 1 mole of $C_5H_{12}$ reacts with 8 moles of $O_2$ gas.

Thus giving us the mole ratio as

Oxygen : Pentane = 8 : 1

4 0

3 years ago

Read 2 more answers

A voltaic cell that uses the reaction PdCl2−4(aq)+Cd(s)→Pd(s)+4Cl−(aq)+Cd2+(aq) has a measured standard cell potential of +1.03

Ghella [55]

Answer : The balanced two-half reactions will be,

Oxidation half reaction : $Cd(s)\rightarrow Cd^{2+}(aq)+2e^-$

Reduction half reaction : $Pd^{2+}(aq)+2e^-\rightarrow Pd(s)$

Explanation :

Voltaic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the galvanic cell or electrochemical cell.

In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

The given redox reaction is:

$PdCl_4^{2-}(aq)+Cd(s)\rightarrow Pd(s)+4Cl^-(aq)+Cd^{2+}(aq)$

The balanced two-half reactions will be,

Oxidation half reaction : $Cd(s)\rightarrow Cd^{2+}(aq)+2e^-$

Reduction half reaction : $Pd^{2+}(aq)+2e^-\rightarrow Pd(s)$

7 0

3 years ago