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3 years ago

Do number 9 Please show work

Physics

1 answer:

Mrrafil [7]3 years ago

7 0

Answer:

a) the acceleration of the block is 8.8 m/s^2

b) the time is 0.33 s

Explanation:

The first that we shall do is to draw the free body diagram, like the one that appears in the attached image. Let's see that the axis x and y were rotated for a better understanding of the equations developed.

We know that the movement with acceleration is the x-axis therefore the total amount of forces will be equal to the product of the mass and the acceleration.

The following step is to calculate the normal force, using the total forces in the y-axis that it is equal to 0. (because there is no movement in the y-axis).

By the definition of the friction force = normal force * friction coefficient. We can calculate the friction force and use it in the equation 1.

For the calculation of the time, we use the kinematics formulas.

Have in count that the body starts moving from the rest therefore v0 = 0

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3 years ago

A ball is dropped from rest at a point 12 m above the ground into a smooth, frictionless chute. The ball exits the chute 2 m abo

Nonamiya [84]

Answer:

29,7 m

Explanation:

We need to devide the problem in two parts:

A) Energy

B) MRUV

Energy:

Since no friction between pint (1) and (2), then the energy conservatets:

Energy = constant ----> Ek(cinética) + Ep(potencial) = constant

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Ep1 = m*g*H1

Ep2= m*g*H2

Then:

Ek2 = m*g*(H1-H2)

By definition of cinetic energy:

m*(V2)²/2 = m*g*(H1-H2) ---> $V2 = \sqrt{(2*g*(H1-H2)}$

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MRUV:

The decomposition of the velocity (V2), gives a for the horizontal component:

V2x = V2*cos(α)

Then the traveled distance is:

X = V2*cos(α)*t.... but what time?

The time what takes the ball hit the ground.

Since: Y3 - Y2 = V2*t + (1/2)*(-g)*t²

In the vertical axis:

Y3 = 0 ; Y2 = H2 = 2 m

Reeplacing:

-2 = 14*t + (1/2)*(-9,81)*t²

solving the ecuation, the only positive solution is:

t = 2,99 sec ≈ 3 sec

Then, for the distance:

X = V2*cos(α)*t = (14 m/s)*(cos45°)*(3sec) ≈ 29,7 m

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4 years ago

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What we know:

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