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n200080 [17]
2 years ago
8

When friction occurs, which of the following types of energy is produced?

Physics
2 answers:
sukhopar [10]2 years ago
8 0

Answer:

heat energy

Explanation:

Friction causes the molecules on rubbing surfaces to move faster, so they have more energy. This gives them a higher temperature, and they feel warmer.

Archy [21]2 years ago
6 0
Hey!

Heat Energy is occurred when friction is produced .

We can relatively observe the warmth on surfaces due to friction too.
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The cart now moves toward the right with an acceleration toward the right of 2.50 m/s2. What does spring scale Fz read? Show you
katrin2010 [14]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

The spring scale F_2 reads  F_2 =  2.4225 \ N

Explanation:

From the question we are told that

      The first force is  F_1  =  10.5 \ N

      The acceleration by which the cart moves to the right is  a = 2.50  \ m/s^2

      The mass of the cart is  m  = 3.231  kg

       

Generally the net force on the cart is  

       F_{net} = F_1 -  F_2

This net force is mathematically represented as

      F_{net} =  m * a

So  

        m*  a =  10 - F_2

        F_2 =  10.5 -  2.5 (3.231)

        F_2 =  2.4225 \ N

 

3 0
3 years ago
What if water didnt have a negative charge?
ArbitrLikvidat [17]
The water molecule, as a whole, has 10 protons and 10 electrons, so it is neutral. ... The unequal sharing of electrons gives the water molecule a slight negative charge near its oxygen atom and a slight positive charge near its hydrogen atoms.
8 0
3 years ago
Nonconjugated β,γ-unsaturated ketones are in base-catalyzed equilibrium with their conjugated α,β-unsaturated isomers. The mecha
Viefleur [7K]

Answer:

Explanation:

The equilibrium mechanism for the reversible acid is catalyzed by the isomerization of non conjugated β, γ- unsaturated ketones, like 3-cyclohexanone to their conjugated α, I²- unsaturated isomers.

Oxygen of the Carbonyl group in the ketone is protonated by the acid and this is followed by the abstraction of an α- hydrogen from the protonated 3-cyclo hexanone to yield ethanol

2-cyclo hexanone can be obtained by acid catalyzation of 3-cyclohexanone isomers through the formation of it's "enol".

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3 years ago
On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const
IceJOKER [234]

Answer:

a)

Explanation:

  • Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:

        x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}   (1)

  • Since the car starts from rest, v₀ =0.
  • We know the value of t = 5 sec., but we need to find the value of a.
  • Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:

       a_{c} =\frac{v_{fc}}{t} = \frac{20m/s}{5s} = 4 m/s2  (2)

  • Replacing a and t in (1):

       x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}  = \frac{1}{2}*a*t^{2} = \frac{1}{2}* 4 m/s2*(5s)^{2} = 50.0 m.  (3)

  • Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
  • Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:

       a_{t} =\frac{-v_{to}}{t} = \frac{-20m/s}{10s} = -2 m/s2  (4)

  • Replacing v₀, at and t in (1), we have:

       x_{ft} = 20m/s*10.0s + \frac{1}{2}*(-2 m/s2)*(10.0s)^{2} = 200m -100m = 100.0m   (5)

  • Therefore, as the truck travels twice as far as the car, the right answer is a).
7 0
3 years ago
Consider two slides, both of the same height. One is long and the other is short. From which slide will the children have a grea
bixtya [17]

Answer:

Explanation:

Sine the plane is horizontal , effect of gravity on horizontal motion will be nil.

Since no friction is acting on it , no horizontal force is acting on it. Since no vertical ,no horizontal force is acting on it , it will have uniform motion ,ie its velocity will remain unchanged during its motion , no matter how long the path is.

So , velocity along the path will remain unchanged.

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