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kolbaska11 [484]
3 years ago
7

A body weighs 100newtons when submerged in water. calculate the upthrust action on the body​

Physics
1 answer:
Andrews [41]3 years ago
7 0

Answer:

Upthrust = 20 N

Explanation:

The question says that "A body weighs 100N in air and 80N when submerged in water. Calculate the upthrust acting on the body ?"

Upthrust is defined as the force when a body is submerged in liquid, then liquid applies a force on it.

ATQ,

Weight of body in air is 100 N

Weight of body in water is 80 N

Upthrust is equal to the weight of body in air minus weight of body in water.

Upthrust = 100 N - 80 N

Upthrust = 20 N

So, 20 N of upthrust is acting on the body.

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Two balls, each with a mass of 0.890 kg, exert a gravitational force of 8.06 × 10−11 n on each other. how far apart are the ball
Bond [772]
This problem involves Newton's universal law of gravitation and the equation to follow would be.

F = GM₁M₂/r²  

Given: M₁ = 0.890 Kg;  M₂ = 0.890 Kg;  F = 8.06 x 10⁻¹¹ N; G = 6.673 X 10⁻¹¹ N m²/Kg²

Solving for distance r = ?

r = √GM₁M₂/F

r = √(6.673 x 10⁻¹¹ N m₂/Kg²)(0.890 Kg)(0.890 Kg)/ 8.06 x 10⁻¹¹ N

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6 0
3 years ago
An isolated system contains a ball at rest 5 meters (m) above the ground. The ball has an initial potential energy of 250 joules
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Answer:

Total mechanical energy is the sum of potential energy plus kinetic energy. The kinetic energy will be 250 [J] and the potential energy is zero, therefore Total mechanical energy will be 250 + 0 =250[J]

Explanation:

This is a problem that applies the principle of energy conservation, i.e. mechanical energy that will be transformed into kinetic energy. We need to identify what kind of energy we have depending on the position of the ball with respect to the reference axis we take.

The reference axis or reference point is the point at which the potential energy is equal to zero, for this case we will take the ground as our reference point.

We know that the potential energy is defined by:

E_{p}=m*g*h\\ where:\\m=mass[kg]\\g=gravity[m/s^2]\\h=elevation[m]

We can clear the mass from this equation:

m=\frac{E_{p} }{(g*h)} \\m=\frac{250 }{(9.81*5)} \\\\m=5.09[kg]

When this body falls its potential energy will decrease but its kinetic energy will increase and reach its maximum value when the ball reaches the ground.

In such a way that its potential energy would be transformed into kinetic energy.

E_{k} = E_{p} \\E_{k} =kinetic energy [J]

Since the potential energy has been transformed all into kinetic energy the amount of energy is conserved, therefore the total mechanical energy will remain the same.

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