The combustion of glucose, C6 H12 O6 (s), produces carbon dioxide, CO2 (g), and water, H2 O(g), according to the equation below.

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The combustion of glucose, C6 H12 O6 (s), produces carbon dioxide, CO2 (g), and water, H2 O(g), according to the equation below.

mc020-1.jpg The enthalpy of the reaction is –2,840 kJ. What is the heat of combustion, per mole, of glucose? –2,840 kJ/mol –473.3 kJ/mol 473.3 kJ/mol 2,840 kJ/mol

Chemistry

2 answers:

Mice21 [21] · Answer 1 · 2022-05-19T17:16:47+03:00

Answer: –2,840 kJ/mol

Explanation: $C_6H_{12}O_6+O_2\rightarrow 6CO_2+6H_2O$ $\Delta H=-2840kJ$

Heat of combustion is the heat produced when 1 mole of the substance is completely oxidized. The production of heat means the reaction is an exothermic process and gives off energy.

According to the given balanced chemical equation:

1 mole of glucose is being completely oxidized to give carbon dioxide and water and thus heat of combustion is -2840 kJ/mol.