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ra1l [238]
3 years ago
6

a cube of iron (cp = 0.450 j/g•°c) with a mass of 55.8 g is heated from 25.0°c to 49.0°c. how much heat is required for this pro

cess?
Chemistry
2 answers:
krek1111 [17]3 years ago
7 0
Q = ?

Cp = 0.450 j/g°C

Δt =  49.0ºC - 25ºC => 24ºC

m = 55.8 g

Q = m x Cp x Δt

Q = 55.8 x 0.450 x 24

Q = 602.64 J

hope this helps! 
lara [203]3 years ago
6 0
The answer is...
...Six-0-Three.
Which is 603.
Just needed some filler to give you it lol
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