a cube of iron (cp = 0.450 j/g•°c) with a mass of 55.8 g is heated from 25.0°c to 49.0°c. how much heat is required for this pro

Question

3 years ago

6

cess?

2 answers:

krek1111 [17] · Answer 1 · 2022-05-15T18:45:34+03:00

7 0

Q = ?

Cp = 0.450 j/g°C

Δt = 49.0ºC - 25ºC => 24ºC

m = 55.8 g

Q = m x Cp x Δt

Q = 55.8 x 0.450 x 24

Q = 602.64 J

hope this helps!

lara [203] · Answer 2 · 2022-05-15T20:36:23+03:00

lara [203]3 years ago

6 0

The answer is...
...Six-0-Three.
Which is 603.
Just needed some filler to give you it lol