Answer:
If a gas has experienced a small increase in volume but has maintained the same pressure and number of moles, the temperature of the gas will DROP.
Explanation:
According to Boyle’s law of ideal gases, volume and temperature of a gas is inversely related, as long as the pressure is kept constant;
P₁V₁/T₁ = P₂V₂/T₂
Therefore, if the volume of the gas increases, the temperature will definitely decrease due to the inverse relationship. The gas will get cooler.
Learn More:
For more on Boyle's Law check out;
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Answer:
- The limiting reagent is N2O4
- 14,09g
Explanation:
- First, we adjust the reaction.
+ 
⇄
- Second, we assume that the participating moles are equal to the stoichiometric ratios because we do not know the amounts of the reagents.
We can determinate what is the limiting reagent comparing of product amounts which can be formed from each reactant.
Using 
to form 
Using to form 
The limiting reagent is N2O4, because can produce only 0, 783 mol of H2O.
This is the minimum measure can be formed of each product.
∴ 
Answer: True
Explanation:
I just took the test and got it right
1) Answer is: molar mas of ammonia is 17.031 g/mol.
M(NH₃) = Ar(N) + 3 · Ar(H) · g/mol.
M(NH₃) = 14.007 + 3 · 1.008 · g/mol.
M(NH₃) = 17.031 g/mol.
2) Answer is: molar mas of lead(II) chloride is 278.106 g/mol.
M(PbCl₂) = Ar(Pb) + 2 · Ar(Cl) · g/mol.
M(PbCl₂) = 207.2 + 2 · 35.453 · g/mol.
M(PbCl₂) = 278.106 g/mol.
3) Answer is: molar mas of acetic acid is 60.052 g/mol.
M(CH₃COOH) = 2 · Ar(C) + 2 · Ar(O) + 4 · Ar(H) · g/mol.
M(CH₃COOH) = 2 · 12.0107 + 2 · 15.9994 + 4 · 1.008 · g/mol.
M(CH₃COOH) = 60.052 g/mol.
