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S_A_V [24]
2 years ago
11

Help me please!

Chemistry
2 answers:
Vlad1618 [11]2 years ago
8 0

Answer:

  • C. 108 grams/100g of H2O

Required number is the vertical coordinate of the intersection point of a line at 60°C with the graph of the KNO₃.

Dmitry_Shevchenko [17]2 years ago
7 0

Answer:

Explanation:

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In the gold foil experiment, what was observed
natima [27]

Rutherford's Gold Foil Experiment proved the existence of a small massive center to atoms, which would later be known as the nucleus of an atom. Ernest Rutherford, Hans Geiger and Ernest Marsden carried out their Gold Foil Experiment to observe the effect of alpha particles on matter.

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3 years ago
1.Give an example of a compound machine (1pt). Explain how at least two simple machines are part of this compound machine (2pts)
Law Incorporation [45]
1) An example of a compound machine could be a pair of Scissors. Their are two different simple machines in the Scissors which make up the compound machine. Both of them being a Lever, and a Fulcrum.

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4 0
3 years ago
It is primarily used as energy storage found in the cell membrane​
Gnesinka [82]

Answer:

ATP—Adenosine triphosphate, a nucleotide which is the most important short-term energy storage compound in cells. It is the “energy currency” of the cell, necessary for practically all metabolic activities. Carbohydrate—A type of organic molecule made of carbon, hydrogen, and oxygen.

4 0
2 years ago
Which of the following is an inorganic compound?<br> AgNO3<br> C6H12<br> СНОН<br> C₂H7N
Lemur [1.5K]

Answer:

AgNO3

Explanation:

Silver nitrate (AgNO3) is an inorganic compound. Organic compounds usually have 1+ C.

4 0
3 years ago
the solubility product Ag3PO4 is: Ksp = 2.8 x 10^-18. What is the solubility of Ag3PO4 in water, in moles per liter?
guapka [62]

Answer : The solubility of Ag_3PO_4 in water is, 1.8\times 10^{-5}mol/L

Explanation :

The solubility equilibrium reaction will be:

Ag_3PO_4\rightleftharpoons 3Ag^++PO_4^{3-}

Let the molar solubility be 's'.

The expression for solubility constant for this reaction will be,

K_{sp}=[Ag^{+}]^3[PO_4^{3-}]

K_{sp}=(3s)^3\times (s)

K_{sp}=27s^4

Given:

K_{sp} = 2.8\times 10^{-18}

Now put all the given values in the above expression, we get:

K_{sp}=27s^4

2.8\times 10^{-18}=27s^4

s=1.8\times 10^{-5}M=1.8\times 10^{-5}mol/L

Therefore, the solubility of Ag_3PO_4 in water is, 1.8\times 10^{-5}mol/L

3 0
3 years ago
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