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Alika [10]
3 years ago
13

What is the value for ∆Soreaction for the following reaction, given the standard entropy values?

Chemistry
1 answer:
Vesnalui [34]3 years ago
6 0
The standard entropy for the substances are as follows:

C6H12O2(s) = -212 
<span>O2(g) = -205 </span>
<span>CO2(g) = -214 </span>
<span>H2O(l) = -70
</span>
We calculate the ∆S°r<span>eaction by the expression:

</span>∆S°rxn = ∆S°products - ∆S° reactants 
∆S°rxn = (212+6x205)-(6x214+6x70) 
∆S°rxn = -262 J/K ------> OPTION 3
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When 18.5 g of HgO(s) is decomposed to form Hg(l) and O2(g), 7.75 kJ of heat is absorbed at standard-state conditions. What is t
taurus [48]

Answer:

The standard enthalpy of formation of HgO is -90.7 kJ/mol.

Explanation:

The reaction between Hg and oxygen is as follows.

\text{Hg(l)}+\frac{1}{2}{O_{2}\rightarrow \text{HgO(s)}

From the given,

Molar mass of HgO = 216.59 g/mol

Mass of HgO decomposed = 18.5 g

Amount of heat absorbed = 7.75 kJ

From the reaction,

The standard  enthalpy of formation = +7.75\times\frac{kJ}{18.5 g}\frac{216.59}{1mol} \,\,= +90.7 kJ/mol

During the decomposition of 1 mol of HgO , 90.7 kJ of energy absorbed.

For the formation of 1 mol of HgO , 90.7 kJ of energy is release

Therefore, the enthalpy of formation of mercury(II)Oxide is -90.7 kJ/mol

5 0
4 years ago
Calculate the hydroxide ion consentration of a solution with pH = 3.25. show all calculations leading to your answer.
lidiya [134]
First you calculate the pOH of the solution:

pH+ pOH = 14

3.25 + pOH = 14

pOH = 14 - 3.25

pOH = 10.75

<span>Concentration of [OH]</span>⁻<span> in solution:
</span>
[ OH⁻ ] = 10 ^{-pOH}

[ OH⁻ ]  = 10^ - 10.75

[OH⁻] = 1.778 x 10⁻¹¹ M

hope this helps !


6 0
3 years ago
Define Acid dissociation constant constant
stiks02 [169]

Answer:

An acid dissociation constant, K a, (also known as acidity constant, or acid-ionization constant) is a quantitative measure of the strength of an acid in solution. It is the equilibrium constant for a chemical reaction ↽ − − ⇀ − + + known as dissociation in the context of acid–base reactions.

Explanation:

6 0
3 years ago
A blank is a condition that strays from normal homeostasis.
AURORKA [14]

homeostatic imbalance is the answer, because it's when the internal environment cannot remain in equilibrium.

8 0
4 years ago
Classify which compounds will dissolve in water and which ones will not dissolve in water.
vredina [299]

Answer:

Dissolves in water: Acetone, 1-propanol, Methanol

Do not dissolve in water: Hexane, Decane

Explanation:

From the principle that like dissolves like,polar substances will dissolve in polar solutions, while non-polar substances will dissolve in non-polar substances.

Water is a polar solution, therefore, polar substances will dissolve in it.From the given options:

Acetone is a polar molecule, therefore, it will dissolve in water.

1-propanol is a polar molecule, therefore, it will dissolve in water.

Hexane is a non-polar molecule, therefore, it will not dissolve in water.

Methanol is a polar molecule, therefore, it will dissolve in water.

Decane is a non-polar molecule, therefore, it will not dissolve in water

6 0
3 years ago
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