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natima [27]
3 years ago
5

A thermometer shows that the temperature of the air in a room has increased.Which type of energy has increased?

Chemistry
1 answer:
liberstina [14]3 years ago
5 0

Kinetic energy has increased.

The <em>Kinetic Molecular Theory</em> of gases states that the average kinetic energy of the molecules of a gas is directly proportional to its Kelvin temperature.

Thus, if the temperature of the air in a room has increased, the average kinetic energy of its molecules has increased.


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What is the mass of 4.5 x 10^22 molecules of hydrogen peroxide (H2O2)? Show your work in the space below.
valentinak56 [21]

Given :

Number of molecules of hydrogen peroxide, N = 4.5 × 10²².

To Find :

The mass of given molecules of hydrogen peroxide.

Solution :

We know, 1 mole of every compound contains Nₐ = 6.022 × 10²³ molecules.

So, number of moles of hydrogen peroxide is :

n = \dfrac{N}{N_a}\\\\n = \dfrac{4.5\times 10^{22}}{6.022\times 10^{23}}\\\\n = 0.0747 \ moles

Now, mass of hydrogen peroxide is given as :

m = n × M.M

m = 0.0747 × 34 grams

m = 2.54 grams

Hence, this is the required solution.

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3 years ago
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otez555 [7]
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3 0
3 years ago
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laila [671]
1.61m :) use the photo below

8 0
3 years ago
Which ionic equation describes a redox reaction? A. Ag(+) + Cl- = AgCl B. 2H(+) + CO3(2-) = CO2 + H2O C. H(+) + OH(-) = H2O D. Z
Gennadij [26K]

<u>Answer:</u> The correct option is D. Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously. It is known as the reaction in which the exchange of electrons takes place.  

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

From the given ionic reactions:

Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu

<u>On the reactant side: </u>

Oxidation number of Zn = 0

Oxidation number of Cu = +2

<u>On the product side: </u>

Oxidation number of Cu = 0

Oxidation number of Zn = +2

As the oxidation number of Zn is increasing from 0 to +2. Thus, it is getting oxidized. Similarly, the oxidation number of Cu is decreasing from +2 to 0. Thus, it is getting reduced. Therefore, forming a redox couple

Hence, the correct option is D. Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu

6 0
3 years ago
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Viktor [21]

Answer:

D.

Vacuole

Explanation:

Hope this helps:)

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