Answer: Newton's law of gravity theory disagrees with Einstein's theory. The last one were named Theory of General Relativity and was discovered and proposed by the physicist Einstein in the year of 1915.
Explanation: Until the beginning of 20 century, the physics were ruled by Isaac Newton's ideas. He believed that the gravity was a force caused by the objects mass on the space, made them to be draw towards each other. Newton thought that the greater the mass of the object, the more intense was its attraction, which would justify the planet's moovements around the sun and how the gravity between them maintain the planets on solar orbit. Concluding, he believed gravity was a immediate force of action, regardless of the distance of the bodies.
Contrary to Newton's law of gravity, in 1915, the physicist Einstein created the Theory of General Relativity, wich discovered that gravity was, in fact, the deformation caused by the attraction of massive celestial bodies. This deformation, related to the Sun, for example, creates a curvature on the space-time and this curvature are followed by the other planets.
So, we can conclude that Newton's law of gravity disagree's with the Theory of General Relativity, once the first believes that light force of attraction are transmitted instantly and, as Einstein already prooved, the gravity influency propagates in the speed of light.
Answer
ω2=82.1 rpm
Explanation:
given required
m1=2.3 kg ω2=?
m2+m3=0.5kg
r1=10 cm
ω1=100 rpm
solution
Using the application of conservation of angular momentum we can solve as follows/
L before collision= L after collision
m1r²ω1=(m1+m2+m3)r²ω2
2.3 kg×0.1² m²×100 rpm=(2.3 kg+0.5 kg)×0.1²m²×ω2
2.3 rpm=0.028×ω2
ω2=82.1 rpm
Answer:
82.2 mL
Explanation:
The process of adding water to a solution to make it more dilute is known as dilution. The formula for dilution is;
C1V1=C2V2
Where;
C1= concentration of stock solution
V1= volume of stock solution
C2= concentration of dilute solution
V2= volume of dilute solution
V2= C1V1/C2
V2= 1.48 × 55.6/ 1.0
V2= 82.2 mL
Answer:
a) Δx₂ = 31*Δt
b) Δx₁ = 977.5 / a
c) a = 23 / Δt
e) Δx₁ = 42.5*Δt
g) Δt = 0.0565 h
i) a = 0.05 m/s²
Explanation:
Given
v₁ = 54 Mi/h
v₂ = 31 Mi/h
a) We apply the formula
Δx₂ = v₂*Δt
⇒ Δx₂ = 31*Δt (Assuming constant speed)
b) We use the formula
v₂² = v₁² - 2*a*Δx₁ ⇒ Δx₁ = (v₁² - v₂²) / (2*a)
⇒ Δx₁ = (54² - 31²) / (2*a)
⇒ Δx₁ = 977.5 / a
c) We use the equation
v₂ = v₁ - a*Δt ⇒ a = (v₁ - v₂) / Δt
⇒ a = (54 - 31) / Δt
⇒ a = 23 / Δt
e) We apply the formula
Δx₁ = v₁*Δt - 0.5*a*Δt²
Δx₁ = 54*Δt - 0.5*(23 / Δt)*Δt²
⇒ Δx₁ = 42.5*Δt
g) If Δx₁ = 2.4 Mi ⇒ 2.4 = 42.5*Δt ⇒ Δt = 0.0565 h
i) If a = 23 / Δt ⇒ a = 23 Mi / 0.0565 h = 407.29 Mi/h²
⇒ a = 0.05 m/s²