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3 years ago

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Determine the largest intensity w of the uniform loading that can be applied to the frame without causing either the average nor

mal stress or the average shear stress at section b–b to exceed σ=19 mpa and τ=24 mpa, respectively.

1 answer:

jeka943 years ago

8 0

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sleet_krkn [62]

Answer:

B: Process #1: Energy is decreasing Process#2: Energy is increasing

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3 years ago

A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. What distance does the truck tra

Natali5045456 [20]

-- The truck begins the scenario moving at 6 m/s.

-- After increasing its speed at the rate of 2 m/s² for 12 seconds,
it has gained (2 x 12) = 24 m/s of speed, and it's then moving
at 30 m/s.

-- The truck's average speed during the 12 seconds is (1/2) (6 + 30) = 18 m/s

-- Traveling at an average speed of 18 m/s for 12 seconds,
the truck travels

(18 m/s) x (12 sec) = 216 meters

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2 years ago

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Is acceleration a <br><br> vector,<br> scalar,<br> both,<br> neither

NemiM [27]

Answer: vector yes

Explanation:

Acceleration is a vector, and thus has a both a magnitude and direction. Acceleration can be caused by either a change in the magnitude or the direction of the velocity.

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2 years ago

According to the law of conservation of energy, the total amount of energy in the universe does not change, but remains constant

Evgen [1.6K]

<span>The statement : According to the law of conservation of energy, the total amount of energy in the universe does not change, but remains constant - is TRUE. The main point which led me to decide is that our universe is the example of a closed system which means there's nothing inside. Hope you will agree with my opinion.
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2 years ago

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A 2.4-m high 200-m2 house is maintained at 22Â°C by an air-conditioning system whose COP, is 3.2. It is estimated that the kitch

kotegsom [21]

Answer:

The amount that is "vented" out by "the fans" is <u>$0.50</u> for 10 hours.

Option: a

<u>Explanation</u>:

"Energy discharged by air in every hour" can be determined by,

$\mathrm{Q}=\mathrm{m}_{\mathrm{air}} \mathrm{C}_{\mathrm{p}} \Delta \mathrm{T}$

Q = heat energy (Joules, J)

m = mass of a substance (kg)

c = specific heat (units J/kg∙K)

$\mathrm{m}_{\mathrm{air}}=\rho \mathrm{v}$

$\text { Density of air } \rho=1.20 \mathrm{kg} / \mathrm{m}^{3}$

$\text { Density of air } \rho=1.20 \times 200 \times 2.4$

$\text { Density of air } \rho=576 \mathrm{kg}$

∆T = 10 hours

$\text { Specific Heat Capacities of Air. The nominal values used for air at } 300 \mathrm{K} \text { are } \mathrm{C_P}=1.00 \mathrm{kJ} / \mathrm{kg} . \mathrm{K}$

Q = 576 × 1.00 × 10

Q = 5760 kJ/hours

W = 1.6 kwh

We know that, “Coefficient of performance” (COP)

$\mathrm{Cop}=\frac{Q}{w}$

$\mathrm{W}=\frac{Q}{\mathrm{cop}}$

Given that, COP = 3.2

$\mathrm{W}=\frac{1.6}{3.2}$

W = 0.5 kwh

The unit cost of electricity is $0.10/kWh

The unit cost of electricity is $0.10/kWh

Unit electricity cost for 10 hours = 0.5 × 10 × 0.1$

Unit electricity cost for 10 hours = $0.5

The amount that is "vented out" by "the fans" is $0.50 for 10 hours.

6 0

3 years ago