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jolli1 [7]
3 years ago
13

What PROPERTIES of elements visibly show periodic trends when their values are graphed?

Chemistry
1 answer:
Scrat [10]3 years ago
3 0
I believe the major periodic trends include; electronegativity, ionization energy, electron affinity, atomic radius, melting point, and the metallic character. Periodic trends, arising from the arrangement of the periodic table, provide chemists with an invaluable tool to quickly predict an element's property.
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A solution is made by dissolving 23.5 grams of glucose (C6H12O6) in 0.245 kilograms of water. If the molal freezing point consta
aalyn [17]

Answer:

- 0.99 °C ≅ - 1.0 °C.

Explanation:

  • We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

m is the molality of the solution (m = moles of solute / kg of solvent = (23.5 g / 180.156 g/mol)/(0.245 kg) = 0.53 m.

<em>∴ ΔTf = (Kf)(m)</em> = (-1.86 °C/m)(0.53 m) =<em> - 0.99 °C ≅ - 1.0 °C.</em>

4 0
4 years ago
Is a burning log an exothermic or endothermic event if the log is the system?
denpristay [2]
It would be endothermic because the log is in the system.
6 0
3 years ago
How many hydrogen atoms are in 5 molecules of isopropyl alcohol, c3h7o?
Oduvanchick [21]
1 molecule of C3H7O has 7 atoms of hydrogen (remember that the numbers to the right of each symbol ara subscripts and they indicate the number of atoms of that element in the molecular formula).

Then 5 molecules will have 5 * 7 atoms of hydrogen.

5 * 7 = 35.

Then the answer is that there are 35 atoms of hydrogen in 5 molecules of isopropyl alcohol, C3H7O
7 0
3 years ago
Read 2 more answers
Hydrogen peroxide can decompose to water and oxygen by the following reaction
mestny [16]
To begin calculating, there is one thing you need to remember :1 mole of H2O2=34.0148 g
Then we have 5.00g of H2O2=5/34.0148=0.146995
As you know decomposition of 2moles now has prodused <span>196kj
So, </span><span>q is made due </span>0.146995 moles of H2O2=(-196/2)*0.146995=-14.40551Kj
I'm sure it will help.
6 0
3 years ago
The complete combustion of octane, C8H18, the main component of gasoline, proceeds as follows: 2C8H18 (l) 25 O2(g) --&gt; 16 CO2
Svet_ta [14]
The ratio of mole number of the reactants and products is equal to the coefficients. So the answer is a. 18.75 mol. b. 35.1 g. c. 1.38 * 10^5 g.
7 0
3 years ago
Read 2 more answers
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