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Tom [10]
3 years ago
12

Which of the following is true regarding the inner transition elements? A. These include all elements in groups 3–12. B. They oc

cupy the d block of the periodic table. C. These include the lanthanides and actinides and do not have f sublevels. D. Their valence electrons can be located in both s and f sublevels.
Chemistry
2 answers:
sesenic [268]3 years ago
7 0

Answer:

D. Their valence electrons can be in both s and f sublevels.

Explanation:

The inner transition elements are those in the two long rows at the bottom of the Periodic Table.

The <em>lanthanide series </em>starts after Ba in Period 6, and the <em>actinide series</em> starts after Ra in Period 7.

Thus, we would predict their electron configurations to be of the form

n\text{s}^{2}(n-2)\text{f}^{n}

However, the energy levels of the <em>n</em>s, (<em>n</em>-1)d, and (<em>n</em>-2)f orbitals are so close in energy that there are many exceptions to our predictions

For example, here are some electron configurations.

La = [Xe]6s²5d (not [Xe]6s²4f)

Ce = [Xe]6s²4f5d (not [Xe]6s²4f²)

Pr = [Xe]6s²4f³ (as predicted)

Thus, their valence electrons can be in both s and f (and sometimes d) sublevels.

A. <em>Wrong</em>. The inner transition elements do not include the elements in Groups 3 to 12. They are the elements between Groups 2 and 3.

B. <em>Wrong.</em> They do not occupy the d block (those are the transition metals). They occupy the f block.

C. <em>Wrong</em>. They include the lanthanides and actinides, but most of them have at least one electron in an f sublevel.

Triss [41]3 years ago
5 0

I think B is your answer

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How many molecules would 3.45 moles of methane (CH4)
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How to answer the question? ⬇️
(Btw this is an example on how to solve it so just letting you know)

To answer this question, you must understand how to convert grams of a molecule into the number of molecules. To do this, you have to utilize the concepts of moles and molar mass.
A mole is just a unit of measurement. Avogadro's number is equal to
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One mole of methane equals 16.04 grams because a molecule of methane has an atomic weight of 16.04. The conversion factor will be 16.04 grams/mole.
48
g
C
H
4
⋅
1
m
o
l
C
H
4
16.04
g
C
H
4
⋅
6.022
⋅
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23
m
c
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s
C
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1
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o
l
C
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1.8021
⋅
10
24
molecules of
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Notice this is a modified T-chart so the grams
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C
H
4
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C
H
4
which corresponds to what the question asks.

This is something else and is not connected with the one above this comment.

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CH4, or 16.04246 grams.

Or

Therefore 3.4 grams of ammonia is equal to 0.1996359579590159 moles of ammonia. Multiplying this by 6.022 * 1023 we get 120220773882919374980000 molecules (or 1.2022 * 1023 molecules). ...
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The molar mass of BeBr2 is
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Answer:

168.812 g/mol

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because there is a 2 after Br you double the atomic mass

79.90(2)= 159.8

To find the molar mass add the atomic masses of each element

9.012+159.8=168.812

3 0
3 years ago
Read 2 more answers
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