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blsea [12.9K]
2 years ago
14

Vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball

held by the musculature in its socket.
If the mass of the eyeball is 7.5 g, a typical value, what is the effective spring constant of the musculature attached to the eyeball
Physics
1 answer:
STALIN [3.7K]2 years ago
4 0

The effective spring constant of the system is 39.6 N/m

Explanation:

The frequency of oscillation of a spring-mass system is given by

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

where

k is the spring constant of the system

m is the mass

In this problem, we have:

f = 29 Hz is the frequency of vibration of the eyeball system

m = 7.5 g = 0.0075 kg is the mass

We can therefore re-arrange the equation to find the effective spring constant of the system. We find:

k=(2\pi f)^2 m = (2\pi (29))^2 (0.0075)=39.6 N/m

#LearnwithBrainly

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A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 starts from rest at t = 0. The wheel has
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Answer:

The total linear acceleration is approximately 0.246 meters per square second.

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a = \sqrt{a_{r}^{2}+a_{t}^{2}} (3)

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r - Radius of the wheel, in meters.

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\omega = \omega_{o}+ \alpha\cdot t (4)

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a \approx 0.246\,\frac{m}{s^{2}}

The total linear acceleration is approximately 0.246 meters per square second.

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