Answer:
I₁/I₂ = 1000
Thus, the sound of siren is 1000 times louder than the sound of wolf's howl.
Explanation:
First, we need to calculate the intensity of both the sounds. The formula for sound level is given as:
L = 10 log[I/I₀]
where,
L = Sound Level in dB
I = Intensity of sound
I₀ = Reference intensity = 10⁻¹² W/m²
<u>FOR SOUND OF SIREN:</u>
L = 120 dB
I = I₁ = ?
Therefore,
120 = 10 log[I₁/10⁻¹²]
log[I₁/10⁻¹²] = (120)/10
log[I₁/10⁻¹²] = 12
I₁/10⁻¹² = 10¹²
I₁ = (10¹²)(10⁻¹²)
I₁ = 1
<u>FOR SOUND OF WOLF'S HOWL:</u>
L = 90 dB
I = I₂ = ?
Therefore,
90 = 10 log[I₂/10⁻¹²]
log[I₂/10⁻¹²] = (90)/10
log[I₂/10⁻¹²] = 9
I₂/10⁻¹² = 10⁹
I₂ = (10⁹)(10⁻¹²)
I₂ = 10⁻³
Now, we divide the intensities:
I₁/I₂ = 1/10⁻³
I₁/I₂ = 10³
<u>I₁/I₂ = 1000</u>
<u>Thus, the sound of siren is 1000 times louder than the sound of wolf's howl.</u>
If that's the case, then
50 units = 0.55 x the input energy
Divide each side by 0.55 :
50 units/0.55 = the input energy =
<span> 90 and 10/11 units</span>
Answer:
Explanation:
Electric field due to long line charge on position of charge at x = 4 m is given as
so we have
now we have
Now electric field due to the charge present at y = 2.0 m
Now total electric field is given as
It would probably be a little thinner than usual