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Blizzard [7]
3 years ago
13

As you walked on the moon, the earth’s gravity would still pull on you weakly and you would still have an earth weight. How larg

e would that earth weight be, compared to your earth weight on the earth’s surface? (Note: The earth’s radius is 6378 km and the distance separating the centers of the earth and moon is 384400 kilometers.)
Physics
1 answer:
vichka [17]3 years ago
6 0

Answer:

g_2 =2\times 10^{-4}g      

Explanation:

given,

radius of earth = 6378 km

distance separating the center of the earth and moon =  384400 km

we know acceleration due to gravity

g = \dfrac{Gm}{r^2}            

g_2 = g\dfrac{r^2}{R^2}                

g_2 = g\dfrac{6378^2}{384400^2}              

g_2 =2\times 10^{-4}g      

hence, the weight of earth compared to the your weight on earths surface is equal to 2 × 10⁻⁴ g.

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What is the gravitational acceleration close to the surface of a planet with a mass of 9ME and radius of 3RE, where ME and RE ar
Papessa [141]

Answer:

9.78 m/s²

Explanation:

To solve this, we use the gravitational formula

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

M = mass of the planet

r = radius of the planet

From the question, we got that the mass of the planet is

M = 9ME, where ME = 5.95*10^24

M = 9 * 5.95*10^24

M = 5.355*10^25 kg

Also, the Radius of the planet, R = 3RE, where RE = 6.37*10^6

R = 3 * 6.37*10^6

R = 1.911*10^7 m

On applying the values of both R and M to the equation, we get

g = GM/r²

g = (6.67*10^-11 * 5.355*10^25) / (1.911*10^7)²

g = 3.57*10^15/3.65*10^14

g = 9.78 m/s²

Therefore, the acceleration due to gravity on the planet is 9.78 m/s²

Please vote brainliest if it helped you <3

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