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DIA [1.3K]
2 years ago
9

Consider the system consisting of the box and the spring, but not Earth. How does the energy of the system when the spring is fu

lly compressed compare to the energy of the system at the moment immediately before the box hits the ground? Justify your answer.
Physics
1 answer:
BabaBlast [244]2 years ago
5 0

Answer:

the energy when it reaches the ground is equal to the energy when the spring is compressed.

Explanation:

For this comparison let's use the conservation of energy theorem.

Starting point. Compressed spring

         Em₀ = K_e = ½ k x²

Final point. When the box hits the ground

         Em_f = K = ½ m v²

since friction is zero, energy is conserved

          Em₀ = Em_f

          1 / 2k x² = ½ m v²

          v = \sqrt{ \frac{k}{m} }     x

Therefore, the energy when it reaches the ground is equal to the energy when the spring is compressed.

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Answer:

15 watt

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The formula for Power is : P = W/t  where;

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3 years ago
In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro
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In order to answer these questions, we need to know the charges on
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I'm beginning to get the creepy feeling that, in return for the generous
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as it were. 

Ok, Rameses:

Elementary charge . . . . .  1.6 x 10⁻¹⁹  coulomb
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          =     ( -2.304 x 10⁻²⁸) / (5.35 x 10⁻¹¹)²

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b).  Centripetal acceleration  = 

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That's an enormous acceleration ... about  7.85 x 10²¹  G's !
More than enough to cause the poor electron to lose its lunch.

It would be so easy to check this work of mine ...
First I calculated the force, then I calculated the centripetal acceleration.
I didn't use either answer to find the other one, and I didn't use  "  F = MA "
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I could just take the ' F ' that I found, and the 'A' that I found, and the
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I'm going to leave that step for you.   Good luck !
4 0
3 years ago
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Answer:

Explanation:

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Filling in:

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