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Yanka [14]
2 years ago
5

Picture is below! Thank you​

Physics
1 answer:
Sergio039 [100]2 years ago
3 0

Answer:

The answer is can speed an object direction!!!!

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Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This
vova2212 [387]

Answer:

1.554\times 10^{32}\ \text{kg}

Explanation:

M = Mass of each star

T = Time period = 15.5 days

v = Orbital velocity = 230 km/s

G = Gravitational constant = 6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2

Radius of orbit is given by

R=\dfrac{vT}{2\pi}

We have the relation

\dfrac{Mv^2}{R}=\dfrac{GM^2}{(2R)^2}\\\Rightarrow M=\dfrac{4Rv^2}{G}\\\Rightarrow M=\dfrac{4\dfrac{vT}{2\pi}v^2}{G}\\\Rightarrow M=\dfrac{2v^3T}{\pi G}\\\Rightarrow M=\dfrac{2\times 230000^3\times 15.5\times 24\times 60\times 60}{\pi\times 6.674\times 10^{-11}}\\\Rightarrow M=1.554\times 10^{32}\ \text{kg}

The mass of each star is 1.554\times 10^{32}\ \text{kg}

6 0
3 years ago
Which of the following would be the best thermal conductor?
Elis [28]
The best thermal conductor is b. metal
4 0
3 years ago
Read 2 more answers
an object at rest has no ________ energy, but it may have ________ energy resulting from its location or structure.
77julia77 [94]

Answer: first blank: kinetic

Second blank: potential

Explanation:

Hope this helps and please consider choosing me for Brainiest!

5 0
2 years ago
Explain how do global winds impact weather in an area?
PolarNik [594]

Answer:

As the warmer air over the equator rises, colder air from the poles rushes toward the equator to take its place. Global winds push air masses around Earth and bring changes in the weather. In the United States, global winds called the prevailing westerlies push air masses from west to east.

Explanation:

6 0
2 years ago
Read 2 more answers
28. A stone is projected at a cliff of height h with an initial speed of 42.0 mls directed at angle θ0 = 60.0° above the horizon
Julli [10]

Answer:

a) 51.8 m, b) 27.4 m/s, c) 142 m

Explanation:

Given:

v₀ = 42.0 m/s

θ = 60.0°

t = 5.50 s

Find:

h, v, and H

a) y = y₀ + v₀ᵧ t + ½ gt²

0 = h + (42.0 sin 60.0) (5.50) + ½ (-9.8) (5.50)²

h = 51.8 m

b) vᵧ = gt + v₀ᵧ

vᵧ = (-9.8)(5.5) + (42.0 sin 60.0)

vᵧ = -17.5 m/s

vₓ = 42.0 cos 60.0

vₓ = 21.0 m/s

v² = vₓ² + vᵧ²

v = 27.4 m/s

c) vᵧ² = v₀ᵧ² + 2g(y - y₀)

0² = (42.0)² + 2(-9.8)(H - 51.8)

H = 142 m

4 0
3 years ago
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