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3 years ago

You should know the location of safety equipment

1 answer:

s2008m [1.1K]3 years ago

7 0

I would say you should use or test it once a week to ensure it is working properly in an active laboratory since it is a workplace with significant chemical hazards so it would give peace of mind to know on a quite regular basis that it can be relied on in case of an emergency like an eye flush for example.

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Atomic bombs are a type of nuclear weapon. List three reasons people might be fascinated by something as dangerous as a nuclear

Evgesh-ka [11]

I'm fascinated with them myself,lol. Anything dangerous really.

1.They have the power to destroy the world.

2.They can wipe out your enemies.

3.If you are crazy enough to use one of these, your enemies will know not to mess with you

6 0

3 years ago

Read 2 more answers

A skateboarder coasts a distance of 20 meters in 4 seconds. What is the person's speed?

yKpoI14uk [10]

Answer:

Explanation:

20/4

5 0

2 years ago

By titration, 15.0 mLmL of 0.1008 MM sodium hydroxide is needed to neutralize a 0.2053-gg sample of an organic acid. What is the

andre [41]

The question is incomplete, here is the complete question:

By titration, 15.0 mL of 0.1008 M sodium hydroxide is needed to neutralize a 0.2053-g sample of an organic acid. What is the molar mass of the acid if it is monoprotic.

Answer: The molar mass of monoprotic acid is 135.96 g/mol

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

For sodium hydroxide:

Molarity of NaOH solution = 0.1008 M

Volume of solution = 15.0 mL

Putting values in above equation, we get:

$0.1008M=\frac{\text{Moles of NaOH}\times 1000}{15.0}\\\\\text{Moles of NaOH}=\frac{(0.1008\times 15.0)}{1000}=0.00151mol$

As, the acid is monoprotic, it contains 1 hydrogen ion

1 mole of $OH^-$ ion of NaOH neutralizes 1 mole of $H^+$ ion of monoprotic acid

So, 0.00151 moles of $OH^-$ ion of NaOH will neutralize $\frac{1}{1}\times 0.00151=0.00151mol$ of $H^+$ ion of monoprotic acid

In monoprotic acid:

1 mole of $H^+$ ion is released by 1 mole of monoprotic acid

So, 0.00151 moles of $H^+$ ion will be released by $\frac{1}{1}\times 0.00151=0.00151mol$ of monoprotic acid

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of monoprotic acid = 0.00151 mole

Given mass of monoprotic acid = 0.2053 g

Putting values in above equation, we get:

$0.00151mol=\frac{0.2053g}{\text{Molar mass of monoprotic acid}}\\\\\text{Molar mass of monoprotic acid}=\frac{0.2053g}{0.00151mol}=135.96g/mol$

Hence, the molar mass of monoprotic acid is 135.96 g/mol

8 0

3 years ago

How will you known that you have reached the equivalence point when titrating the NaOH solution with HCl?

Nitella [24]

Answer:

When the solution (with phenolphthalein) changes to colorless

Explanation:

When titrating with HCl is common to add phenolphthalein as an acid-base indicator.

Phenolphthalein is pink or fucsia when added into a basic solution. On the other hand when it is in acid solutions, is colorless.

So, when titrating, the NaOH solution will be initialy pink due to the phenolphthalein and when reaching the equivalence point, that color will fade out into colorless. This is how you know you hace reached the equivalent point.

6 0

3 years ago

PLEASE HELP IM STUGGLING

Gre4nikov [31]

Answer:

8)acids are electron pair acceptors and bases are electron pair donors

9)monoprotic

10)weak acids

7 0

3 years ago