Answer:
11.72 grams
Explanation:
Let the equilibrium concentration of BrCl be y
Initial concentration of Br2 = number of moles ÷ volume = (0.979×1000/160) ÷ 199 = 0.031 M
Initial concentration of Cl2 = (1.075×1000/71) ÷ 199 = 0.076 M
From the equation of reaction
1 mole of Br2 reacted with 1 mole of Cl2 to form 2 moles of BrCl
Therefore, equilibrium concentration of Br2 = (0.031 - 0.5y) M while that of Cl2 = (0.076 - 0.5y) M
Kp = [BrCl]^2/[Br2][Cl2]
1.1×10^-4 = y^2/(0.031 - 0.5y)(0.076 - 0.5y)
y^2/0.002356-0.0535y+0.25y^2 = 0.00011
y^2/0.00011 = 0.002356-0.0536y+0.25y^2
9090.9y^2-0.25y^2+0.0536y-0.002356 = 0
9090.65y^2+0.0535y-0.002356 = 0
The value of y must be positive and is obtained using the quadratic formula
y = [-0.0535 + sqrt(0.0535^2 - 4×9090.65×-0.002356)] ÷ 2(9090.65) = 9.2025/18181.3 = 0.00051 M
Mass of BrCl = concentration×volume×MW = 0.00051×199×115.5 = 11.72 grams
Answer:
Bond length.
Explanation:
During formation of a covalent bond between atoms the total potential energy of the new molecule is less than the sum of energy of the two atoms. This is the energy orientation for the formation of bond. This is due to gain of stability by full filling the octet of the atoms. In covalent bond sharing of electrons occur. When two atoms approach each other there is decrease in energy till the bond length of the molecule, after this if we try to minimize the distance between atoms, the repulsion forces start to act their role.
Answer:
5a. 13.5 moles of F₂
5b. 3.33 moles of Ar.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
3F₂ + 2Ar —> 2ArF₃
From the balanced equation above,
3 moles of F₂ reacted with 2 moles of Ar to produce 2 moles of ArF₃.
5a. Determination of the number of mole of fluorine, F₂, needed to produce 9 moles of ArF₃.
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of ArF₃.
Therefore, Xmol of F₂ will react to produce 9 moles of ArF₃ i.e
Xmol of F₂ = (3 × 9)/2
Xmol of F₂ = 13.5 moles
Thus, 13.5 moles of F₂ is needed.
5b. Determination of the number of mole of Ar needed to react with 5 moles F₂.
From the balanced equation above,
3 moles of F₂ reacted with 2 moles of Ar.
Therefore, 5 moles of F₂ will react with = (5 × 2)/3 = 3.33 moles of Ar.
Thus, 3.33 moles of Ar was consumed.
Answer:
MgCl2
Explanation:
Just did it... got it wrong but it showed me the right answer, you welcome
