Given:
0.060 mol of NiC2O4
Ksp = 4 x 10⁻¹⁰
1.0 L of solution
Kf of Ni(NH3)6 2⁺ = 1.2 x 10⁹
<span>NiC2O4 + 6NH3 ⇋ Ni(NH3)6 2+ + 2O4 2- </span>
<span>NiC2O4 ⇋ Ni 2+ + C2O4 2- ...Ksp </span>
<span>Ni2+ + 6NH3 ⇋ Ni(NH3)6 2+...Kf </span>
Ksp * Kf = (4 x 10⁻¹⁰) * (1.2 x 10⁹) = 0.48
K = 0.48 = [Ni(NH3)6 2+][C2O4 2-] / [NH3]⁶<span>
</span>0.48 = (0.060)² / [NH3]⁶<span> ... (dissolved C2O4 2- = 0.060M)
</span><span>[NH3]</span>⁶<span> = (0.060)</span>²<span> / 0.48 = </span>0.0036 / 0.48 = 0.0075
NH3 = ⁶√0.0075
NH3 = 0.44 M
D).thermal energy
Hope this helps.
Answer:
The last answer is right they get half of the mothers genes and half of the fathers genes.
Answer: 1.037M
Explanation:
Since the rate constant unit is per seconds, therefore it is a first order reaction.
First order reaction equation is given as
InA= -kt +InAo
Where,Ao is the initial concentration of reactant =0.600M
A is the concentration of reactant at a specifies time t=3×60=180s
and k is the rate constant
InA = -6.50×10^-3 ×180 +In(0.6)
InA = -1.17 + 0.5108
InA= -1.680
A = e-1.680
A= 1.037M
Therefore the concentration after 3minutes is 1.037M
