Answer:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
Explanation:
Chemical equation:
CO + O₂ → CO₂
Balanced chemical equation:
2CO + O₂ → 2CO₂
The standard enthalpy for the formation of CO = -110.5 kj/mol
The standard enthalpy for the formation of O₂ = 0 kj/mol
The standard enthalpy for the formation of CO₂ = -393.5 kj/mol
Now we will put the values in equation:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol + 0]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol]
ΔH0reaction = -283 kj/mol
Answer : The chemical symbol for the element that results from this process is, (Ar) for argon.
Explanation :
Electron capture : In this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. Simply, a proton and an electron combines together to form a neutron. Mass number does not change in this process.
The equation for the given reaction is,
Thus, the chemical symbol for the element that results from this process is, argon (Ar).
Answer:
At nine, it can still count as neutral.
Explanation:
The ph scale goes from 0 (acid) to 14 (alkaline/base). The middle would be seven, which is neutral. Nine has more alkalinity than a true neutral, but I believe it is close enough to the middle to not count as a base.
EDTA is a complex used to determine water hardness. The reaction between EDTA and CaCO₃ is in 1:1 ratio. To solve this problem, we must know the moles of CaCO₃ present (otherwise we can't solve the problem). Suppose you have 0.5 moles of CaCO₃. Since the ratio is 1:1, it would also need 0.5 moles EDTA. Then,
Volume = Moles/Molarity = 0.5 moles/0.05 M = 10 L of EDTA