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GenaCL600 [577]

4 years ago

12

Any change in the system from one equilibrium state to another is called: A) Path B) Process C) Cycle D) None of the above

1 answer:

dexar [7]4 years ago

7 0

Answer:

B) Process

Explanation:

In thermodynamics a process is a passage of a thermodynamic system from an initial to a final state of thermodynamic equilibrium.

A thermodynamic process path is the series of states through which a system passes from an initial to a final state.

Cycle is a process in which initial and final state are identical.

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Water is pumped steadily through a 0.10-m diameter pipe from one closed pressurized tank to another tank. The pump adds 4.0 kW o

jekas [21]

Complete Question

Complete Question is attached below.

Answer:

$V'=5m/s$

Explanation:

From the question we are told that:

Diameter $d=0.10m$

Power $P=4.0kW$

Head loss $\mu=10m$

$\frac{P_1}{\rho g}+\frac{V_1^2}{2g}+Z_1+H_m=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}+Z_2+\mu$

$\frac{300*10^3}{\rho g}+35+Hm=\frac{500*10^3}{\rho g}+15+10$

$H_m=(\frac{200*10^3}{1000*9.8}-10)$

$H_m=10.39m$

Generally the equation for Power is mathematically given by

$P=\rho gQH_m$

Therefore

$Q=\frac{P}{\rho g H_m}$

$Q=\frac{4*10^4}{1000*9.81*10.9}$

$Q=0.03935m^3/sec$

Since

$Q=AV'$

Where

$A=\pi r^2\\A=3.142 (0.05)^2$

$A=7.85*10^{-3}$

Therefore

$V'=\frac{0.03935m^3/sec}{7.85*10^{-3}}$

$V'=5m/s$

5 0

3 years ago

The particle travels along the path defined by the parabola y=0.5x2, where x and y are in ft. If the component of velocity along

JulsSmile [24]

Answer:

D=41.48 ft

$a=54.43\ ft/s^2$

Explanation:

Given that

y=0.5 x²

Vx= 2 t

We know that

$V_x=\dfrac{dx}{dt}$

At t= 0 ,x=0

$x=\int V_x.dt$

At t= 3 s

$x=\int_{0}^{3} 2t.dt$

$x=[t^2\left\right ]_0^3$

x= 9 ft

When x= 9 ft then

y= 0.5 x 9² ft

y= 40.5 ft

So distance from origin is

x= 9 ft ,y= 40.5 ft

$D=\sqrt{9^2+40.5^2} \ ft$

D=41.48 ft

$a_x=\dfrac{dV_x}{dt}$

Vx= 2 t

$a_x= 2\ ft/s^2$

At t= 3 s , x= 9 ft

y=0.5 x²

$a_y=\dfrac{d^2y}{dt^2}$

y=0.5 x²

$\dfrac{dy}{dt}=x\dfrac{dx}{dt}$

$\dfrac{d^2y}{dt^2}=\left(\dfrac{dx}{dt}\right)^2+x\dfrac{d^2x}{dt^2}$

Given that

$\dfrac{dx}{dt}=2t$

$\dfrac{dx}{dt}=2\times 3$

$\dfrac{dx}{dt}=6\ ft/s$

$a_y=\dfrac{d^2y}{dt^2}=6^2+9\times 2\ ft/s^2$

$a_y=54\ ft/s^2$

$a=\sqrt{a_x^2+a_y^2}\ ft/s^2$

$a=\sqrt{2^2+54^2}\ ft/s^2$

$a=54.43\ ft/s^2$

7 0

3 years ago

Anyone want to play among us with me the code is MMJSUF

Katarina [22]

Answer:

sure

Explanation:

6 0

3 years ago

Read 2 more answers

Consider the time domain waveforms below on the left. Match waveforms (a) - (e) to their respective frequency spectrum represent

lozanna [386]

Answer:

(a) ------(3). (b)------(1) (c)-----(5) (d)------(2) ------ (e) -----4

Note: Kindly find an attached copy of the diagram associated with the solution to the question below.

Sources: the diagram to this question was researched from Quizlet

Explanation:

Solution

(1) Part (a)a waveform has a high frequency components compared to another waveform. the corresponding frequency components should be high.

So for the wave form a the corresponding frequency spectrum is (3)

(2) For part (b), waveform has three harmonics, the corresponding frequency spectrum is (1)

(3) The time domain waveform plot (c) is a sine wave but there exists a dc component.

Thus x[0] ≠0

For (c) the corresponding frequency spectrum is (5)

(4) For part (d) the corresponding frequency spectrum is (2)

(5) A sine wave is made of a single frequency only and its spectrum is a single point

For (e) the corresponding frequency spectrum is (4)

3 0

3 years ago

Engineers will redesign their products when they find flaws. TRUE O False

nataly862011 [7]

Answer:

true

Explanation:

6 0

3 years ago