SMAW and GMAW use constant current arc welding machines.<br><br> True<br><br> False

A piston-cylinder device contains 1.329 kg of nitrogen gas at 120 kPa and 27 degree C. The gas is now compressed slowly in a pol

Shtirlitz [24]

Answer:-0.4199 J/k

Explanation:

Given data

mass of nitrogen(m)=1.329 Kg

Initial pressure $\left ( P_1\right )$ =120KPa

Initial temperature $\left ( T_1\right )=27\degree \approx$ 300k

Final volume is half of initial

R=particular gas constant

Therefore initial volume of gas is given by

PV=mRT

V=0.986\times 10^{-3}

Using $PV^{1.49}$ =constant

$P_{1}V^{1.49}$ = $P_2\left (\frac{V}{2}\right )$

$P_2$ =337.066KPa

$V_2$ = $0.493\times 10^{-3} m^{3}$

and entropy is given by

$\Delta s$ = $C_v \ln \left (\frac{P_2}{P_1}\right )$ + $C_p \ln \left (\frac{V_2}{V_1}\right )$

Where, $C_v$ = $\frac{R}{\gamma-1}$ =0.6059

$C_p$ = $\frac{\gamma R}{\gamma -1}$ =0.9027

Substituting values we get

$\Delta s$ = $0.6059\times\ln \left (\frac{337.066}{120}\right )$ + $0.9027 \ln \left (\frac{1}{2}\right )$

$\Delta s$ =-0.4199 J/k

4 0

4 years ago

If you were to plot the voltage versus the current for a given circuit, what would you expect the slope of the line to be? If no

Brut [27]

Answer:

Part 1: It would be a straight line, current will be directly proportional to the voltage.

Part 2: The current would taper off and will have negligible increase after the voltage reaches a certain value. Graph attached.

Explanation:

For the first part, voltage and current have a linear relationship as dictated by the Ohm's law.

V=I*R

where V is the voltage, I is the current, and R is the resistance. As the Voltage increase, current is bound to increase too, given that the resistance remains constant.

In the second part, resistance is not constant. As an element heats up, it consumes more current because the free sea of electrons inside are moving more rapidly, disrupting the flow of charge. So, as the voltage increase, the current does increase, but so does the resistance. Leaving less room for the current to increase. This rise in temperature is shown in the graph attached, as current tapers.

7 0

4 years ago

If the feedforward path of a control system contains at least one integrating element, then the output continues to change as lo

Thepotemich [5.8K]

Answer:

The attached system shows that there’s an integrator between the point where disturbance enters the system and error measuring element. A any time when R(s)=0 then

$\frac {C(s)}{D(s)}=\frac {G(s)}{1+G_c(s)G(s)}$ and considering that $E(s)=D(s)-G_c(s)C(s)$ then