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erica [24]
3 years ago
8

Without motorcycle riders are at risk of severe injury in a crash ?

Engineering
2 answers:
astra-53 [7]3 years ago
6 0
The answer is A
Proper protection
nekit [7.7K]3 years ago
5 0

Answer:

The correct option is;

A. proper protection

Explanation:

Motorcycle riders ride the motorcycle while at some level of speed while  having the entire body exposed to be a major part of any collision.

Injuries sustained from motorcycle accidents are several times more severe than injuries sustained by occupants of a car that is fully protected by the metallic panel in the same and even more serious accident scenarios

Hence, motorcycle riders require adequate protection by putting on available motorcyclist safety gear

Therefore, to reduce the risk of severe injury n a crash, motorcycle riders require proper protection.

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A rectangular channel 3-m-wide carries 12 m^3/s at a depth of 90cm. Is the flow subcritical or supercritical? For the same flowr
hram777 [196]

Answer:

Super critical

1.2 m

Explanation:

Q = Flow rate = 12\ \text{m}^3/\text{s}

w = Width = 3 m

d = Depth = 90 cm = 0.9 m

A = Area = wd

v = Velocity

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Q=Av\\\Rightarrow v=\dfrac{Q}{wd}\\\Rightarrow v=\dfrac{12}{3\times 0.9}\\\Rightarrow v=4.44\ \text{m/s}

Froude number is given by

Fr=\dfrac{v}{\sqrt{gd}}\\\Rightarrow Fr=\dfrac{4.44}{\sqrt{9.81\times 0.9}}\\\Rightarrow F_r=1.5

Since F_r>1 the flow is super critical.

Flow is critical when Fr=1

Depth is given by

d=(\dfrac{Q^2}{gw^2})^{\dfrac{1}{3}}\\\Rightarrow d=(\dfrac{12^2}{9.81\times 3^2})^{\dfrac{1}{3}}\\\Rightarrow d=1.2\ \text{m}

The depth of the channel will be 1.2 m for critical flow.

4 0
2 years ago
Is the sample mean always the most frequently occurring value? If so, explain why. If not, give an example.
Ugo [173]

Answer:

No the sample mean is not the most frequently occurring data.

Explanation:

If we take a number of observation in an experiment the most frequently repeating value is known as mode of data.

Mean of data is the the value to which all the given observational values are closest.

Consider a given set of observations as

1,1,1,1,1,5,4,3,4

The Mean of the above data set is\bar{x}=\frac{1+1+1+1+1+1+5+4+3+4}{10}=2 While as the most often repeating value is 1 which is not equal to mean  

6 0
3 years ago
How much wood could a wood chuck chuk if a wood chuck could chuck wood
WINSTONCH [101]

Answer:

A woodchuck would chuck as much wood as a woodchuck could chuck if a woodchuck could chuck wood

Explanation:

LOL

7 0
3 years ago
Read 2 more answers
The Reynolds number is the major parameter that relates fluid flow momentum to friction forces. How is the Reynolds number defin
fiasKO [112]

Answer:

Reynolds number determines whether a flow is laminar or turbulent flow.

Explanation:

Reynolds number is defined as ratio of inertia force to the viscous force. it is a dimension less  number. Reynolds number is used to describe the type of flow in a fluid whether it is laminar flow or turbulent flow. Reynolds number is denoted by Re.

When Reynolds number is in the range of 0 to 2000, the flow is considered to be laminar.

When Reynolds number is in the range of 2000 to 4000, the flow is considered to be transition.

And when Reynolds number is more than 4000, the flow is turbulent flow.

                     The boundary layer thickness for a fluid is given by

                                      δ = \frac{5\times x}{\sqrt{Re}}

where δ is boundary layer thickness

           x is distance from the leading edge

           Re is Reynolds number

Thus from the above boundary layer thickness equation, we can see that the boundary layer thickness varies inversely to square root of reynolds number.

8 0
3 years ago
) 1.3kg of gold at 300K comes in thermal contact with 2.1kg copper at 400K. The specific heats of Au and Cu are 126 J/kg-K and 3
scZoUnD [109]

Answer: Equilibrium temperature they reach is 383 K

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of gold = 1.3 kg

m_2 = mass of copper = 2.1 kg

T_{final} = final temperature = ?

T_1 = temperature of gold= 300 K

T_2 = temperature of copper = 400 K

c_1 = specific heat of gold = 126J/kgK

c_2 = specific heat of copper = 386J/kgK

Now put all the given values in equation (1), we get

1.3\times 126\times (T_{final}-300)=-[2.1\times 386\times (T_{final}-400)]

T_{final}=383K

Thus equilibrium temperature they reach is 383 K

7 0
3 years ago
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