Answer:
Super critical
1.2 m
Explanation:
Q = Flow rate = 
w = Width = 3 m
d = Depth = 90 cm = 0.9 m
A = Area = wd
v = Velocity
g = Acceleration due to gravity = 

Froude number is given by

Since
the flow is super critical.
Flow is critical when 
Depth is given by

The depth of the channel will be 1.2 m for critical flow.
Answer:
No the sample mean is not the most frequently occurring data.
Explanation:
If we take a number of observation in an experiment the most frequently repeating value is known as mode of data.
Mean of data is the the value to which all the given observational values are closest.
Consider a given set of observations as
1,1,1,1,1,5,4,3,4
The Mean of the above data set is
While as the most often repeating value is 1 which is not equal to mean
Answer:
A woodchuck would chuck as much wood as a woodchuck could chuck if a woodchuck could chuck wood
Explanation:
LOL
Answer:
Reynolds number determines whether a flow is laminar or turbulent flow.
Explanation:
Reynolds number is defined as ratio of inertia force to the viscous force. it is a dimension less number. Reynolds number is used to describe the type of flow in a fluid whether it is laminar flow or turbulent flow. Reynolds number is denoted by Re.
When Reynolds number is in the range of 0 to 2000, the flow is considered to be laminar.
When Reynolds number is in the range of 2000 to 4000, the flow is considered to be transition.
And when Reynolds number is more than 4000, the flow is turbulent flow.
The boundary layer thickness for a fluid is given by
δ = 
where δ is boundary layer thickness
x is distance from the leading edge
Re is Reynolds number
Thus from the above boundary layer thickness equation, we can see that the boundary layer thickness varies inversely to square root of reynolds number.
Answer: Equilibrium temperature they reach is 383 K
Explanation:

As we know that,

.................(1)
where,
q = heat absorbed or released
= mass of gold = 1.3 kg
= mass of copper = 2.1 kg
= final temperature = ?
= temperature of gold= 300 K
= temperature of copper = 400 K
= specific heat of gold = 
= specific heat of copper = 
Now put all the given values in equation (1), we get
![1.3\times 126\times (T_{final}-300)=-[2.1\times 386\times (T_{final}-400)]](https://tex.z-dn.net/?f=1.3%5Ctimes%20126%5Ctimes%20%28T_%7Bfinal%7D-300%29%3D-%5B2.1%5Ctimes%20386%5Ctimes%20%28T_%7Bfinal%7D-400%29%5D)

Thus equilibrium temperature they reach is 383 K